C++ 在密码提示下隐藏用户输入
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Hide user input on password prompt
提问by dom0
Possible Duplicate:
Read a password from std::cin
可能重复：
从 std::cin 读取密码
I don't work normally with the console, so my question is maybe very easy to answer or impossible to do .
我不能正常使用控制台，所以我的问题可能很容易回答或不可能做到。
Is it possible to "decouple" cinand cout, so that what I type into the console doesn't appear directly in it again?
是否可以“解耦”cin和cout，以便我在控制台中输入的内容不会再次直接出现在其中？
I need this for letting the user typing a password and neither me nor the user normally wants his password appearing in plaintexton the screen.
我需要这个来让用户输入密码，我和用户通常都不希望他的密码出现在plaintext屏幕上。
I tried using std::cin.tieon a stringstream, but everything I type is still mirrored in the console.
我尝试std::cin.tie在 a 上使用stringstream，但我输入的所有内容仍会反映在控制台中。
回答by
From How to Hide Text:
从如何隐藏文本：
Windows
视窗
#include <iostream>
#include <string>
#include <windows.h>
using namespace std;
int main()
{
HANDLE hStdin = GetStdHandle(STD_INPUT_HANDLE);
DWORD mode = 0;
GetConsoleMode(hStdin, &mode);
SetConsoleMode(hStdin, mode & (~ENABLE_ECHO_INPUT));
string s;
getline(cin, s);
cout << s << endl;
return 0;
}//main
cleanup:
清理：
SetConsoleMode(hStdin, mode);
tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
Linux
Linux
#include <iostream>
#include <string>
#include <termios.h>
#include <unistd.h>
using namespace std;
int main()
{
termios oldt;
tcgetattr(STDIN_FILENO, &oldt);
termios newt = oldt;
newt.c_lflag &= ~ECHO;
tcsetattr(STDIN_FILENO, TCSANOW, &newt);
string s;
getline(cin, s);
cout << s << endl;
return 0;
}//main
回答by James Kanze
You're really asking about two unrelated issues.
Calling cin.tie( NULL )decouples std::cinand std::coutcompletely. But it doesn't affect anything at a lower level. And at the lowest level, at least under Windows and Unix, std::cinand std::coutare both connected to the same device at the system level, and it is that device (/dev/ttyunder Unix) which does the echoing; you can even redirect standard out to a file, and the console will still echo input.
你真的在问两个不相关的问题。
调用cin.tie( NULL )解耦std::cin和std::cout完全。但它不会影响较低级别的任何内容。而在最底层，至少在 Windows 和 Unix 下，std::cin并且std::cout在系统级别都连接到同一设备，并且是该设备（/dev/tty在 Unix 下）进行回显；你甚至可以将标准输出重定向到一个文件，控制台仍然会回显输入。
How you turn off this echoing depends on the system; the easiest solution is probably to use some sort of third party library, like curses or ncurses, which provides a higher level interface, and hides all the system dependencies.
如何关闭这种回声取决于系统；最简单的解决方案可能是使用某种第三方库，如 curses 或 ncurses，它们提供更高级别的接口，并隐藏所有系统依赖项。
回答by zw324
Use getch()to get the input instead of using cin, so the input will not be shown (quoting wiki):
使用getch()以获得输入，而不是使用的cin，所以输入将不会被显示（引用维基）：
int getch(void) Reads a character directly from the console without buffer, and without echo.
int getch(void) 直接从控制台读取一个字符，没有缓冲区，没有回显。
This is really C, not C++, but it might suit you.
这确实是 C，而不是 C++，但它可能适合您。
Also, there's another linkhere.
此外，这里还有另一个链接。
