来自字典的 Python 更新对象
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Python update object from dictionary
提问by chakrit
Is there a built-in function/operator I could use to unpack values from a dictionary and assign it into instance variables?
是否有内置函数/运算符可用于从字典中解压缩值并将其分配给实例变量？
This is what I intend to do:
这是我打算做的：
c = MyClass()
c.foo = 123
c.bar = 123
# c.foo == 123 and c.bar == 123
d = {'bar': 456}
c.update(d)
# c.foo == 123 and c.bar == 456
Something akin to dictionary update()which load values from another dictionary but for plain object/class instance?
类似于update()从另一个字典加载值但用于普通对象/类实例的字典？
回答by Jehiah
there is also another way of doing it by looping through the items in d. this doesn't have the same assuption that they will get stored in c.__dict__which isn't always true.
还有另一种方法是循环遍历 d 中的项目。这与它们将被存储在c.__dict__其中的假设不同，这并不总是正确的。
d = {'bar': 456}
for key,value in d.items():
setattr(c,key,value)
or you could write a updatemethod as part of MyClassso that c.update(d)works like you expected it to.
或者您可以编写一个update方法作为其中的一部分，MyClass以便按照c.update(d)您的预期工作。
def update(self,newdata):
for key,value in newdata.items():
setattr(self,key,value)
check out the help for setattr
查看 setattr 的帮助
setattr(...) setattr(object, name, value) Set a named attribute on an object; setattr(x, 'y', v) is equivalent to ''x.y = v''.
setattr(...) setattr(object, name, value) Set a named attribute on an object; setattr(x, 'y', v) is equivalent to ''x.y = v''.
回答by S.Lott
Have you tried
你有没有尝试过
f.__dict__.update( b )
?
?
回答by hyperboreean
回答by Trong Pham
You can try doing:
你可以尝试这样做：
def to_object(my_object, my_dict):
for key, value in my_dict.items():
attr = getattr(my_object, key)
if hasattr(attr, '__dict__'):
to_object(attr, value)
else:
setattr(my_object, key, value)
obj = MyObject()
data = {'a': 1, 'b': 2}
to_object(obj, data)
