Python 将变量传递给子进程调用
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4795190/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Passing variables to a subprocess call
提问by rsouthard
I am trying to pass my variables from raw_inputto my subprocess command. I am new to Python. Any help would he appreciated.
我试图将我的变量传递raw_input给我的子进程命令。我是 Python 的新手。任何帮助他将不胜感激。
#!/usr/bin/python
import subprocess
print "\nWhat user name"
username = str(raw_input('username: '))
print "\nWhat is the user id"
userid = int(raw_input('Enter user id: '))
print "\nWhat is the user\'s primary group?"
primarygroup = int(raw_input('Enter group: '))
print "\nWhat is the user\'s secondary group?"
secondarygroup = int(raw_input('Enter group: '))
subprocess.call(['useradd' '-m' '-g' _primarygroup '-G' _secondarygroup '-u' _userid _username])
print"\nThe user has been added"
回答by ThiefMaster
Try separating the values with commas:
尝试用逗号分隔值：
subprocess.call(['useradd', '-m', '-g', _primarygroup, '-G', _secondarygroup, '-u', _userid, _username])
See http://docs.python.org/library/subprocess.html#subprocess.call- It takes an array where the first argument is the program and all other arguments are passed as arguments to the program.
请参阅http://docs.python.org/library/subprocess.html#subprocess.call- 它采用一个数组，其中第一个参数是程序，所有其他参数作为参数传递给程序。
Also don't forget to check the return value of the function for a zero return code which means "success" unless it doesn't matter for your script if the user was added successfully or not.
另外不要忘记检查函数的返回值是否为零返回代码，这意味着“成功”，除非用户是否成功添加对您的脚本无关紧要。
回答by miku
Try to add commas between your list items:
尝试在列表项之间添加逗号：
subprocess.call(['useradd', '-m', '-g', _primarygroup, '-G', _secondarygroup, \
'-u' ,_userid, _username])
subprocess.calltakes the same arguments as subprocess.Popen:
subprocess.call采用与 相同的参数subprocess.Popen：
argsshould be a string, or a sequenceof program arguments.
args应该是一个字符串，或一系列程序参数。
Edit
编辑
To turn all your arguments into strings at once you could you a list comprehension:
要将所有参数一次转换为字符串，您可以使用列表理解：
args = ['useradd', '-m', '-g', _primarygroup, '-G', _secondarygroup, \
'-u' ,_userid, _username]
str_args = [ str(x) for x in args ]
回答by user225312
subprocess.call(['useradd', '-m','-g', _primarygroup, '-G', _secondarygroup, '-u', _userid, _username])
Pass a listto subprocess.call
传递list给subprocess.call
回答by Daniel Luevano Alonso
You can create the arg string first and then just past this variable to the subprocess.call. For example:
您可以先创建 arg 字符串，然后将此变量传递给 subprocess.call。例如：
projects_csv_fn = 'projects_csv_2.csv'
prjects_json_fn = 'projects.json'
args ='python json_to_csv.py id ' + prjects_json_fn + ' ' + projects_csv_fn
subprocess.call(args, shell=True)
回答by Javi
have you tried just using 'xxx{0}'.format(variable)? see link1or link2
你试过只使用'xxx{0}'.format(variable)吗？ 见链接 1或链接 2
subprocess.run(['useradd', '-m', '-g {0}'.format(_primarygroup), '-G {0}'.format(_secondarygroup), '-u {0}'.format(_userid)], capture_output=True)
or
或者
subprocess.call(['useradd', '-m', '-g {0}'.format(_primarygroup), '-G {0}'.format(_secondarygroup), '-u {0}'.format(_userid)])
just worked fine to me
对我来说很好用
