使用变量从python执行shell脚本
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Execute shell script from python with a variable
提问by Vince
I have this code:
我有这个代码：
opts.info("Started domain %s (id=%d)" % (dom, domid))
I want to execute a shell script with the parameter domidfrom above.
Something like this:
我想用domid上面的参数执行一个shell脚本。像这样的东西：
subprocess.call(['test.sh %d', domid])
How does it work?
它是如何工作的？
I've tried it with:
我已经尝试过：
subprocess.call(['test.sh', domid])
But I get this error:
但我收到此错误：
File "/usr/lib/xen-4.1/bin/xm", line 8, in <module>
main.main(sys.argv)
File "/usr/lib/xen-4.1/bin/../lib/python/xen/xm/main.py", line 3983, in main
_, rc = _run_cmd(cmd, cmd_name, args)
File "/usr/lib/xen-4.1/bin/../lib/python/xen/xm/main.py", line 4007, in _run_cmd
return True, cmd(args)
File "<string>", line 1, in <lambda>
File "/usr/lib/xen-4.1/bin/../lib/python/xen/xm/main.py", line 1519, in xm_importcommand
cmd.main([command] + args)
File "/usr/lib/xen-4.1/bin/../lib/python/xen/xm/create.py", line 1562, in main
dom = make_domain(opts, config)
File "/usr/lib/xen-4.1/bin/../lib/python/xen/xm/create.py", line 1458, in make_domain
subprocess.call(['test.sh', domid])
File "/usr/lib/python2.7/subprocess.py", line 493, in call
return Popen(*popenargs, **kwargs).wait()
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
raise child_exception
TypeError: execv() arg 2 must contain only strings
采纳答案by Paco
Like this ?
像这样 ？
subprocess.call(['test.sh', str(domid)])
Documentation is available on the python website
文档可在python 网站上找到
回答by Prahalad Deshpande
You need to call the shell script in the below manner from your python script:
您需要从您的 python 脚本以下列方式调用 shell 脚本：
subprocess.call(['test.sh', domid])
Refer herefor the documentation of the subprocess module. In the above script, we pass a list to the callmethod where the first element is the program to be executed and the remaining elements within the list are the arguments to the program.
有关 subprocess 模块的文档，请参阅此处。在上面的脚本中，我们将一个列表传递给call方法，其中第一个元素是要执行的程序，列表中的其余元素是程序的参数。
回答by LearnOPhile
A simple solution to remember:
要记住的简单解决方案：
import os
bashCommand = "source script.sh"
os.system(bashCommand)
回答by Murtaza Pitalwala
I was also looking to do the same thing as this post. Execute Shell Script from python with variable (with variable I think it means with command line argument).
我也想做和这篇文章一样的事情。使用变量从python执行Shell脚本（使用变量我认为这意味着使用命令行参数）。
I did the following to get the results. I am sharing in case other people are looking for the same answer.
我做了以下工作以获得结果。我正在分享以防其他人正在寻找相同的答案。
import os
arglist = 'arg1 arg2 arg3'
bashCommand = "/bin/bash script.sh " + arglist
os.system(bashCommand)
which worked just fine for me.
这对我来说很好用。
I also, after more reading it suggests that it would be better to use subprocess.Popen, if you want to get the results back for display purposes. I am logging everything out to another file with in the bash script, so I don't really have a need for subprocess.
我也，经过更多阅读后，它建议最好使用 subprocess.Popen，如果您想将结果返回用于显示目的。我正在使用 bash 脚本将所有内容都记录到另一个文件中，所以我真的不需要子进程。
I hope it helps.
我希望它有帮助。
import os
os.system("cat /root/test.sh")
#!/bin/bash
x='1'
while [[ $x -le 10 ]] ; do
echo $x: hello
sleep 1
x=$(( $x + 1 ))
done
arglist = 'arg1 arg2 arg3'
bashCommand = 'bash /root/test.sh ' + arglist
os.system(bashCommand)
1: hello arg1 arg2 arg3
2: hello arg1 arg2 arg3
3: hello arg1 arg2 arg3
4: hello arg1 arg2 arg3
5: hello arg1 arg2 arg3
