php 删除时间戳的时间部分
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Remove time part of a timestamp
提问by David Weng
How can I remove time part of a timestamp?
如何删除时间戳的时间部分？
So for example turn 1310571061to 1310565600which is the plain date timestamp.
因此，例如转1310571061来1310565600这是明摆着的日期戳。
回答by Brad
strtotime(date("Y-m-d", 1310571061));
That should do it for you.
那应该为你做。
回答by Brad
In case you wanted a mathematical solution:
如果你想要一个数学解决方案：
$time=1310571061;
echo floor($time/86400)*86400;
There are 86,400 seconds in 24 hours (which is the length of a typicalday, but not all... see DST). Since our timestamps are in UTC, this shouldn't be a problem. You can divide that by the number of seconds in a day, drop the remainder, and multiply back out.
24 小时内有 86,400 秒（这是典型一天的长度，但不是全部……参见夏令时）。由于我们的时间戳采用 UTC，因此这应该不是问题。您可以将其除以一天中的秒数，减去余数，然后再乘以返回。
回答by xtempore
Using a DateTime object can be helpful, and also can make the code more readable...
使用 DateTime 对象可能会有所帮助，并且还可以使代码更具可读性......
$dt = new DateTime();
$dt->setTimestamp(1310571061);
echo $dt->format('Y-m-d, H:i:s') . "\r\n";
$dt->setTime(0, 0, 0);
echo $dt->format('Y-m-d, H:i:s');
Result...
结果...
2011-07-14, 03:31:01
2011-07-14, 00:00:00
2011-07-14, 03:31:01
2011-07-14, 00:00:00
The choice of whether to use raw timestamps or DateTime objects will depend a lot on the implementation needs, but generally speaking DateTime objects will go a long way towards reducing confusion and errors that can crop up especially around Timezone issues and Daylight Saving Time issues.
选择是使用原始时间戳还是 DateTime 对象将在很大程度上取决于实现需求，但一般来说 DateTime 对象将大大有助于减少可能出现的混淆和错误，尤其是在时区问题和夏令时问题方面。
回答by Shef
Try:
尝试：
<?php
$ts = '1310571061';
echo strtotime(date('Y-m-d 00:00:00', $ts));
?>
回答by Rohit Srivastava
$pubdate='2003-02-19T00:00:00.000-05:00';
$da = strtotime($pubdate);
echo $dat = date('Y-m-d', $da);
The answer is like :"2003-02-19"
答案就像：“2003-02-19”
Thank You
谢谢你
回答by Elo Kitty
This is what I usually do:
这是我通常的做法：
your_timestamp = pd.to_datetime(your_timestamp.strftime(format="%x"))
The function strftimewill convert your_timestampto a string without the time component. Then the function pd.to_datetimewill convert it back to a Timestampwithout the time component.
该函数strftime将转换your_timestamp为没有时间分量的字符串。然后该函数pd.to_datetime会将其转换回Timestamp没有时间分量的 a 。
回答by Nicola Peluchetti
You could do:
你可以这样做：
$date = strotime(date("y/m/d", $timestamp));
