Python 数据框，从列表中设置索引
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时间：2020-08-19 21:54:32 来源:igfitidea点击:
dataframe, set index from list
提问by vandelay
Is it possible when creating a dataframe from a list, to set the index as one of the values?
从列表创建数据框时是否可以将索引设置为值之一？
import pandas as pd
tmp = [['a', 'a1'], ['b',' b1']]
df = pd.DataFrame(tmp, columns=["First", "Second"])
First Second
0 a a1
1 b b1
And how I'd like it to look:
我希望它看起来如何：
First Second
a a a1
b b b1
采纳答案by Alexander
>>> pd.DataFrame(tmp, columns=["First", "Second"]).set_index('First', drop=False)
First Second
First
a a a1
b b b1
回答by ragesz
If you don't want index name:
如果您不想要索引名称：
df = pd.DataFrame(tmp, columns=["First", "Second"], index=[i[0] for i in tmp])
Result:
结果：
First Second
a a a1
b b b1
回答by Aman Singh Kamboj
Change it to list before assigning it to index
在将其分配给索引之前将其更改为列表
df.index = list(df["First"])
