bash 如何在bash脚本中循环？
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How to loop in bash script?
提问by co-worker
i have following lines in a bash script under Linux:
我在 Linux 下的 bash 脚本中有以下几行：
...
mkdir max15
mkdir max14
mkdir max13
mkdir max12
mkdir max11
mkdir max10
...
how is the syntax for putting them in a loop, so that i don't have to write the numbers (15,14..) ?
将它们放入循环中的语法如何，以便我不必写数字 (15,14..) ？
回答by ghostdog74
with bash, no need to use external commands like seqto generate numbers.
使用 bash，无需使用诸如seq生成数字之类的外部命令。
for i in {15..10}
do
mkdir "max${i}"
done
or simply
或者干脆
mkdir max{01..15} #from 1 to 15
mkdir max{10..15} #from 10 to 15
say if your numbers are generated dynamically, you can use C style for loop
说如果你的数字是动态生成的，你可以使用 C 风格的循环
start=10
end=15
for((i=$start;i<=$end;i++))
do
mkdir "max${i}"
done
回答by Chen Levy
No loop needed for this task:
此任务不需要循环：
mkdir max{15..10} max0{9..0}
... but if you need a loop construct, you can use one of:
...但如果你需要一个循环结构，你可以使用以下之一：
for i in $(seq [ <start> [ <step> ]] <stop>) ; do
# you can use $i here
done
or
或者
for i in {<start>..<stop>} ; do
# you can use $i here
done
or
或者
for (( i=<start> ; i < stop ; i++ )) ; do
# you can use $i here
done
or
或者
seq [ <start> [ <step> ]] <stop> | while read $i ; do
# you can use $i here
done
Note that this last one will not keep the value of $i outside of the loop, due to the |that starts a sub-shell
请注意，最后一个不会将 $i 的值保留在循环之外，因为|它启动了一个子 shell
回答by eumiro
for a in `seq 10 15`; do mkdir max${a}; done
seqwill generate numbers from 10to 15.
seq将生成从10到 的数字15。
EDIT:I was used to this structure since many years. However, when I observed the other answers, it is true, that the {START..STOP}is much better. Now I have to get used to create directories this much nicer way: mkdir max{10..15}.
编辑：多年来我已经习惯了这种结构。但是，当我观察其他答案时，确实如此，后者{START..STOP}要好得多。现在我必须习惯以这种更好的方式创建目录：mkdir max{10..15}.
回答by chrisaycock
for i in {1..15} ; do
mkdir max$i
done
