将整数附加到字符串 Bash 脚本 OSX
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Append Integer To String Bash Script OSX
提问by user1227118
I am attempting to write a bash script that loops exactly 20 times and then appends each number in the loop to the variable with a string "group". The output of each variable should be group1, group2, group3, and so on. Unfortunately i am unable to get this to work. Here is my code thus far:
我正在尝试编写一个 bash 脚本，该脚本正好循环 20 次，然后将循环中的每个数字附加到带有字符串“group”的变量中。每个变量的输出应该是 group1、group2、group3 等等。不幸的是，我无法让它发挥作用。到目前为止，这是我的代码：
#!/bin/bash
USERNUM=0
USERPREFIX='group'
for (( i = 1 ; i <= 20; i++ ))
do
USERNUM=$(($USERNUM+1))
USERCREATE=$(($USERPREFIX+$USERNUM))
echo $USERCREATE
done
I am trying to run this script under OSX 10.6. Any help is greatly appreciated.
我正在尝试在 OSX 10.6 下运行此脚本。任何帮助是极大的赞赏。
回答by Ignacio Vazquez-Abrams
USERCREATE="$USERPREFIX$USERNUM"
