javascript 如何解决这个“类型错误：在对象中找不到函数 getTime”？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/21363333/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to fix this "TypeError: Cannot find function getTime in object"?
提问by craftApprentice
I'm using this function in a Google Apps Script:
我在 Google Apps 脚本中使用这个函数：
function dateDiffYears() {
var datas = [ [Date(2005, 7, 20), Date(2004, 2, 17)],
[Date(2008, 9, 1),Date(2007, 5, 25)],
[Date(2010, 11, 2),Date(2010, 7, 28)],
[Date(2014, 0, 24),Date(2013, 1, 27)] ];
for (var i= 0; i < datas.length; i++){
var d1 = datas[i][0];
var d2 = datas[i][1];
Logger.log("d2 = " + d2 );
Logger.log("d2 instanceof Date = " + (d2 instanceof Date) );
Logger.log("d1 = " + d1 );
Logger.log("d1 instanceof Date = " + (d1 instanceof Date) );
var t2 = d2.getTime();
var t1 = d1.getTime();
Logger.log("d1 = " + t1);
Logger.log("d2 = " + t2);
var result = parseInt( (t2-t1)/(24*3600*1000) );
Logger.log("diff = " + result);
}
}
As I can remember, this function worked in the past. But now, when I run it, I got this error message: TypeError: Cannot find function getTime in object Sun Jan 26 2014 10:23:10 GMT-0200 (BRST). (line 22,(line 22 is var t2 = d2.getTime();). I don't understand this error. What is wrong with the Date(yyyy, mm, dd) formate? And why the error message is talking about today date (ex:Sun Jan 26 2014 10:23:10 GMT-0200 (BRST)) since I'm not using New Date()?
我记得，这个功能在过去有效。但是现在，当我运行它时，我收到此错误消息：（TypeError: Cannot find function getTime in object Sun Jan 26 2014 10:23:10 GMT-0200 (BRST). (line 22,第 22 行是var t2 = d2.getTime();）。我不明白这个错误。Date(yyyy, mm, dd) 格式有什么问题？为什么错误消息是在谈论今天的日期（例如：），Sun Jan 26 2014 10:23:10 GMT-0200 (BRST)因为我没有使用New Date()？
How to fix it?
如何解决？
回答by T.J. Crowder
I don't understand this error because clearly Sun Jan 26 2014 10:23:10 GMT-0200 (BRST) is a date object.
我不明白这个错误，因为很明显 Sun Jan 26 2014 10:23:10 GMT-0200 (BRST) 是一个日期对象。
Clearly it isn'ta Dateobject. Perhaps it's a string, or some Google Apps Script object that gets output a bit like a date but doesn't have a getTimefunction. Perhaps it's a Rangeobject containing a date.
显然它不是一个Date对象。也许它是一个字符串，或者一些 Google Apps Script 对象，它的输出有点像日期但没有getTime函数。也许它是一个Range包含日期的对象。
If it were a Dateobject, it would have the getTimemethod.
如果它是一个Date对象，它就会有getTime方法。
How to fix it?
如何解决？
Without knowing how you get d1and d2, it's impossible to say. If it's a Rangeobject, for instance, perhaps you can get the date via getValue.
不知道你是怎么得到d1和的d2，就不可能说出来。Range例如，如果它是一个对象，也许您可以通过getValue.
The first step is to figure out what the object actually is. Perhaps setting a breakpoint on the first line of dataDiffand inspecting the arguments.
第一步是弄清楚对象实际上是什么。也许在第一行设置断点dataDiff并检查参数。
回答by RobG
In your code:
在您的代码中：
function dateDiffYears() {
var datas = [ [Date(2005, 7, 20), Date(2004, 2, 17)],
[Date(2008, 9, 1),Date(2007, 5, 25)],
[Date(2010, 11, 2),Date(2010, 7, 28)],
[Date(2014, 0, 24),Date(2013, 1, 27)] ];
creates arrays of strings representing the current date and time, it doesn't create Date objects. Further, all arguments are ignored. Date(andything in here)is equivalent to:
创建表示当前日期和时间的字符串数组，它不创建 Date 对象。此外，所有参数都将被忽略。Date(andything in here)相当于：
(new Date()).toString();
per ECMA-262:
根据ECMA-262：
All of the arguments are optional; any arguments supplied are accepted but are completely ignored. A String is created and returned as if by the expression (new Date()).toString()…
所有参数都是可选的；接受提供的任何参数，但完全忽略。一个字符串被创建并返回，就像由表达式 (new Date()).toString()...
