c# 中是否可以使用二维列表？
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Are 2 dimensional Lists possible in c#?
提问by CasperT
I'd like to set up a multidimensional list. For reference, I am working on a playlist analyzer.
我想建立一个多维列表。作为参考，我正在研究播放列表分析器。
I have a file/file-list, which my program saves in a standard list. One line from the file in each list entry.
我有一个文件/文件列表，我的程序将其保存在标准列表中。每个列表条目中的文件中的一行。
I then analyze the list with regular-expressions to find specific lines. Some of the data/results from the lines needs to be put into a new multidimensionallist; since I don't know how many results/data I'll end up with, I can't use a multidimensional array.
然后我用正则表达式分析列表以找到特定的行。行中的一些数据/结果需要放入新的多维列表中；因为我不知道最终会得到多少结果/数据，所以我不能使用多维数组。
Here is the data I want to insert:
这是我要插入的数据：
List
(
[0] => List
(
[0] => Track ID
[1] => Name
[2] => Artist
[3] => Album
[4] => Play Count
[5] => Skip Count
)
[1] => List
(
And so on....
Real Example:
真实例子：
List
(
[0] => List
(
[0] => 2349
[1] => The Prime Time of Your Life
[2] => Daft Punk
[3] => Human After All
[4] => 3
[5] => 2
)
[1] => List
(
So yeah, mlist[0][0] would get TrackID from song 1, mlist[1][0] from song 2 etc.
所以是的，mlist[0][0] 会从歌曲 1 中获取 TrackID，从歌曲 2 中获取 mlist[1][0] 等等。
But I am having huge issues creating a multidimensional list. So far I have come up with
但是我在创建多维列表时遇到了很大的问题。到目前为止，我想出了
List<List<string>> matrix = new List<List<string>>();
But I haven't really had much more progress :(
但我并没有真正取得更多进展:(
采纳答案by Jon Skeet
Well you certainly canuse a List<List<string>>where you'd then write:
那么你当然可以使用一个List<List<string>>你会写的地方：
List<string> track = new List<string>();
track.Add("2349");
track.Add("The Prime Time of Your Life");
// etc
matrix.Add(track);
But why would you do that instead of building your own class to represent a track, with Track ID, Name, Artist, Album, Play Count and Skip Count properties? Then just have a List<Track>.
但是为什么要这样做而不是构建自己的类来表示具有轨道 ID、名称、艺术家、专辑、播放次数和跳过次数属性的曲目？然后只需一个List<Track>.
回答by Spoike
As Jon Skeetmentioned you can do it with a List<Track>instead. The Track class would look something like this:
正如Jon Skeet提到的，你可以用 aList<Track>来代替。Track 类看起来像这样：
public class Track {
public int TrackID { get; set; }
public string Name { get; set; }
public string Artist { get; set; }
public string Album { get; set; }
public int PlayCount { get; set; }
public int SkipCount { get; set; }
}
And to create a track list as a List<Track>you simply do this:
要创建曲目列表，List<Track>您只需执行以下操作：
var trackList = new List<Track>();
Adding tracks can be as simple as this:
添加轨道可以像这样简单：
trackList.add( new Track {
TrackID = 1234,
Name = "I'm Gonna Be (500 Miles)",
Artist = "The Proclaimers",
Album = "Finest",
PlayCount = 10,
SkipCount = 1
});
Accessing tracks can be done with the indexing operator:
可以使用索引运算符来访问轨道：
Track firstTrack = trackList[0];
Hope this helps.
希望这可以帮助。
回答by paul jamison
another work around which i have used was...
我使用过的另一项工作是......
List<int []> itemIDs = new List<int[]>();
itemIDs.Add( new int[2] { 101, 202 } );
The library i'm working on has a very formal class structure and i didn't wan't extra stuff in there effectively for the privilege of recording two 'related' ints.
我正在使用的库有一个非常正式的类结构，我不想为了记录两个“相关”整数的特权而在那里有效地添加额外的东西。
Relies on the programmer entering only a 2 item array but as it's not a common item i think it works.
依赖于程序员只输入一个 2 项数组，但由于它不是一个常见的项目，我认为它有效。
回答by SoIAS
I used:
我用了：
List<List<String>> List1 = new List<List<String>>
var List<int> = new List<int>();
List.add("Test");
List.add("Test2");
List1.add(List);
var List<int> = new List<int>();
List.add("Test3");
List1.add(List);
that equals:
这等于：
List1
(
[0] => List2 // List1[0][x]
(
[0] => Test // List[0][0] etc.
[1] => Test2
)
[1] => List2
(
[0] => Test3
回答by Val
You can also use DataTable - you can define then the number of columns and their types and then add rows http://www.dotnetperls.com/datatable
您还可以使用 DataTable - 您可以定义列数及其类型，然后添加行 http://www.dotnetperls.com/datatable
回答by Jordan LaPrise
This is the easiest way i have found to do it.
这是我发现的最简单的方法。
List<List<String>> matrix= new List<List<String>>(); //Creates new nested List
matrix.Add(new List<String>()); //Adds new sub List
matrix[0].Add("2349"); //Add values to the sub List at index 0
matrix[0].Add("The Prime of Your Life");
matrix[0].Add("Daft Punk");
matrix[0].Add("Human After All");
matrix[0].Add("3");
matrix[0].Add("2");
To retrieve values is even easier
检索值更容易
string title = matrix[0][1]; //Retrieve value at index 1 from sub List at index 0
回答by Ben
Here is how to make a 2 dimensional list
这是制作二维列表的方法
// Generating lists in a loop.
List<List<string>> biglist = new List<List<string>>();
for(int i = 1; i <= 10; i++)
{
List<string> list1 = new List<string>();
biglist.Add(list1);
}
// Populating the lists
for (int i = 0; i < 10; i++)
{
for(int j = 0; j < 10; j++)
{
biglist[i].Add((i).ToString() + " " + j.ToString());
}
}
textbox1.Text = biglist[5][9] + "\n";
Be aware of the danger of accessing a location that is not populated.
请注意进入无人居住的位置的危险。
回答by DDK
You can also..do in this way,
你也可以..这样做，
List<List<Object>> Parent=new List<List<Object>>();
List<Object> Child=new List<Object>();
child.Add(2349);
child.Add("Daft Punk");
child.Add("Human");
.
.
Parent.Add(child);
if you need another item(child), create a new instance of child,
如果您需要另一个项目（子项），请创建一个新的子项实例，
Child=new List<Object>();
child.Add(2323);
child.Add("asds");
child.Add("jshds");
.
.
Parent.Add(child);
回答by Joe Horrell
Here's a little something that I made a while ago for a game engine I was working on. It was used as a local object variable holder. Basically, you use it as a normal list, but it holds the value at the position of what ever the string name is(or ID). A bit of modification, and you will have your 2D list.
这是我不久前为我正在开发的游戏引擎制作的一些东西。它被用作本地对象变量持有者。基本上，您将它用作普通列表，但它保存字符串名称（或 ID）所在位置的值。稍作修改，您将拥有 2D 列表。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace GameEngineInterpreter
{
public class VariableList<T>
{
private List<string> list1;
private List<T> list2;
/// <summary>
/// Initialize a new Variable List
/// </summary>
public VariableList()
{
list1 = new List<string>();
list2 = new List<T>();
}
/// <summary>
/// Set the value of a variable. If the variable does not exist, then it is created
/// </summary>
/// <param name="variable">Name or ID of the variable</param>
/// <param name="value">The value of the variable</param>
public void Set(string variable, T value)
{
if (!list1.Contains(variable))
{
list1.Add(variable);
list2.Add(value);
}
else
{
list2[list1.IndexOf(variable)] = value;
}
}
/// <summary>
/// Remove the variable if it exists
/// </summary>
/// <param name="variable">Name or ID of the variable</param>
public void Remove(string variable)
{
if (list1.Contains(variable))
{
list2.RemoveAt(list1.IndexOf(variable));
list1.RemoveAt(list1.IndexOf(variable));
}
}
/// <summary>
/// Clears the variable list
/// </summary>
public void Clear()
{
list1.Clear();
list2.Clear();
}
/// <summary>
/// Get the value of the variable if it exists
/// </summary>
/// <param name="variable">Name or ID of the variable</param>
/// <returns>Value</returns>
public T Get(string variable)
{
if (list1.Contains(variable))
{
return (list2[list1.IndexOf(variable)]);
}
else
{
return default(T);
}
}
/// <summary>
/// Get a string list of all the variables
/// </summary>
/// <returns>List string</string></returns>
public List<string> GetList()
{
return (list1);
}
}
}
