Linux sprintf 用 \n 写入字符串
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sprintf write to string with \n
提问by brunoais
I have this code:
我有这个代码：
str1= "a";
str2= "b";
sprintf(string, "0 %s %s\n", str1, str2);
string then contains:
字符串然后包含：
"0 a b"
instead of (what I want):
而不是（我想要的）：
"0 a b "
How can I solve that?
我该如何解决？
Note: I place the quoting of the var string inside " so that you could understand the situation.
Edit:
注意：我将 var 字符串的引用放在 " 中，以便您了解情况。
编辑：
Problem solvedI added 1 to the size and it worked. I don't completely understand why but it's solved
问题解决了我在大小上加了 1 并且它起作用了。我不完全明白为什么但它已经解决了
回答by Joshua Weinberg
It sounds like what you want is sprintf(string, "0 %s %s\n\n", str1, str2);
听起来你想要的是 sprintf(string, "0 %s %s\n\n", str1, str2);
In your example the string actually contains "0 a b\n" which means that anything printed after the \nwill appear on the next line. If you want a blank line below it, you need another line break.
在您的示例中，字符串实际上包含“0 ab\n”，这意味着在 之后打印的任何内容都\n将出现在下一行。如果你想在它下面有一个空行，你需要另一个换行符。
回答by Some programmer dude
If you are on a Windows computer you might need \r\ninstead of just the newline. The library should handle it though.
如果您使用的是 Windows 计算机，则可能需要\r\n而不仅仅是换行符。图书馆应该处理它。
回答by wannik
Allocate enough space for string
分配足够的空间 string
#include <stdio.h>
#include <stdarg.h>
main() {
char string[7];
char str1[] = "a";
char str2[] = "b";
sprintf(string, "0 %s %s\n", str1, str2);
printf("%s", string);
}
回答by Sodved
Looks like its working for me. I put brackets []around the string to prove it.
看起来它对我有用。我[]在字符串周围加了括号来证明这一点。
Have a look here: http://ideone.com/3rbwF
看看这里：http: //ideone.com/3rbwF
