Python:检查网络接口是否已启动
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Python: check whether a network interface is up
提问by Ricky Robinson
In Python, is there a way to detect whether a given network interfaceis up?
在 Python 中,有没有办法检测给定的网络接口是否已启动?
In my script, the user specifies a network interface, but I would like to make sure that the interface is up and has been assigned an IP address, before doing anything else.
在我的脚本中,用户指定了一个网络接口,但在执行其他任何操作之前,我想确保该接口已启动并已分配 IP 地址。
I'm on Linuxand I am root.
我在Linux 上,我是root。
采纳答案by Ricky Robinson
As suggested by @Gabriel Samfira, I used netifaces
. The following function returns True when an IP address is associated to a given interface.
正如@Gabriel Samfira 所建议的,我使用了netifaces
. 当 IP 地址与给定接口关联时,以下函数返回 True。
def is_interface_up(interface):
addr = netifaces.ifaddresses(interface)
return netifaces.AF_INET in addr
The documentation is here
文档在这里
回答by svinota
回答by André Pires
You can see the content of the file in /sys/class/net/<interface>/operstate
. If the content is not down
then the interface is up.
您可以在/sys/class/net/<interface>/operstate
. 如果内容不是,down
则界面已启动。
回答by user18197
The interface can be configured with an IP address and not be up so the accepted answer is wrong. You actually need to check /sys/class/net/<interface>/flags
. If the content is in the variable flags, flags & 0x1
is whether the interface is up or not.
接口可以配置一个 IP 地址,但不能启动,因此接受的答案是错误的。您实际上需要检查/sys/class/net/<interface>/flags
. 如果内容在变量flags中,flags & 0x1
就是接口是否up。
Depending on the application, the /sys/class/net/<interface>/operstate
might be what you really want, but technically the interface could be up and the operstate
down, e.g. when no cable is connected.
根据应用的不同,这/sys/class/net/<interface>/operstate
可能是您真正想要的,但从技术上讲,接口可能是向上和operstate
向下的,例如当没有连接电缆时。
All of this is Linux-specific of course.
当然,所有这些都是特定于 Linux 的。
回答by ofirule
回答by myuce
If the question is about checking if the cable is conencted (FreeBSD);
如果问题是关于检查电缆是否已连接(FreeBSD);
[status for status in run.cmd(' /usr/local/bin/sudo ifconfig %s ' % interface).split("\t") if status.strip().startswith("status")][0].strip().endswith("active")
For this, no api support so far :( ...
为此,到目前为止还没有 api 支持:( ...