Java 如何使用内容类型 XML 和查询参数触发 HTTP 帖子？
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How to fire HTTP post with content type XML along with query parameters?
提问by Ioan
I am trying to fire a POST request. The data I am sending is XML format (I am doing this via JAXB), but I have to send along a request parameter. My problem is regarding the Content-Type(I've added some comments in the code). Which one should I use ?
我正在尝试触发 POST 请求。我发送的数据是 XML 格式（我通过 JAXB 执行此操作），但我必须发送请求参数。我的问题是关于Content-Type（我在代码中添加了一些注释）。我应该使用哪一种？
See below my code :
请参阅下面我的代码：
private V callAndGetResponse(K request, Class<K> requestClassType, Class<V> responseClassType) throws Exception {
JAXBContext jaxbContext = JAXBContext.newInstance(requestClassType, responseClassType);
Marshaller marshaller = jaxbContext.createMarshaller();
// set properties on marshaller
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(Marshaller.JAXB_ENCODING, charset);
marshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders", String.format(XML_HEADER_FORMAT, dtd));
marshaller.marshal(request, System.out);
URL wsUrl = new URL(primaryEndpointUrl);
HttpURLConnection connection = openAndPrepareConnection(wsUrl);
tryToMarshallWsRequestToOutputStream(request, marshaller, connection);
printDebug(connection);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
Object response = unmarshaller.unmarshal(connection.getInputStream());
// cleanup
connection.disconnect();
return responseClassType.cast(response);
}
private HttpURLConnection openAndPrepareConnection(URL wsUrl) throws IOException {
HttpURLConnection connection = (HttpURLConnection) wsUrl.openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Accept", "application/xml");
connection.setRequestProperty("Accept-Charset", charset);
// Both types ? Doesn't work
connection.setRequestProperty("Content-Type", "application/xml;application/x-www-form-urlencoded");
// Only app/xml ? it seems that query param is not added to request
connection.setRequestProperty("Content-Type", "application/xml");
// Only app/query param ? it seems that xml is not added to request
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
return connection;
}
private void tryToMarshallWsRequestToOutputStream(K request, Marshaller jaxbForRequestMarshaller,
HttpURLConnection connection) throws JAXBException, IOException {
OutputStream outputStream = null;
try {
outputStream = connection.getOutputStream();
jaxbForRequestMarshaller.marshal(request, outputStream);
addQueryParameters(outputStream);
}
finally {
tryToClose(outputStream);
}
}
private void addQueryParameters(OutputStream outputStream) throws IOException {
String value = "none";
String query = String.format("xmlmsg=%s", URLEncoder.encode(value, charset));
outputStream.write(query.getBytes(charset));
}
protected void tryToClose(OutputStream outputStream) throws IOException {
if (outputStream != null) {
outputStream.close();
}
}
Thanks a lot!
非常感谢！
采纳答案by Kylar
Ok, there's two different issues that you're dealing with:
好的，您正在处理两个不同的问题：
1) Content-Type of the body. In this case, if your body is an XML body, so it should be:
1) 正文的内容类型。在这种情况下，如果您的正文是 XML 正文，那么它应该是：
Content-Type: application/xml; charset="utf-8"
2) The fact that your query parameters are being stripped off (or ignored). This is a more complicated problem. When a form is submitted via an HTTP Post, it is often sent as query string params, and this looks like what might be happening. Can you get a wire trace of what's being sent? It may be that you'll need to parse the parameters off yourself instead of trying to parse them as a form body.
2）您的查询参数被剥离（或忽略）的事实。这是一个更复杂的问题。当表单通过 HTTP Post 提交时，它通常作为查询字符串参数发送，这看起来像是可能发生的事情。你能得到正在发送什么的线路追踪吗？您可能需要自己解析参数，而不是尝试将它们解析为表单体。
If you need to send two different types of data, you may consider sending something like a multipart form, or sending one body type, and adding extra data as a header.
如果您需要发送两种不同类型的数据，您可以考虑发送类似多部分表单的内容，或发送一种正文类型，并添加额外数据作为标头。
