Python:列表理解列表
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/21507319/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Python: List comprehension list of lists
提问by Jean-Luc
I have a list of lists, and would like to use list comprehension to apply a function to each element in the list of lists, but when I do this, I end up with one long list rather than my list of lists.
我有一个列表列表,并且想使用列表理解将函数应用于列表列表中的每个元素,但是当我这样做时,我最终得到一个长列表而不是我的列表列表。
So, I have
所以我有
x = [[1,2,3],[4,5,6],[7,8,9]]
[number+1 for group in x for number in group]
[2, 3, 4, 5, 6, 7, 8, 9, 10]
But I want to get
但我想得到
[[2, 3, 4], [5, 6, 7], [8, 9, 10]]
How do I go about doing this?
我该怎么做?
采纳答案by Booster
Use this:
用这个:
[[number+1 for number in group] for group in x]
Or use this if you know map:
或者,如果您知道地图,请使用它:
[map(lambda x:x+1 ,group) for group in x]
回答by Shirutzen
lista = [[i+3*(j-1) for i in range(1,4)] for j in range(1,4)]
print(lista)
# outputs [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

