在 Python 中 URL 解码 UTF-8
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Url decode UTF-8 in Python
提问by swordholder
I have spent plenty of time as far as I am newbie in Python.
How could I ever decode such a URL:
就我是 Python 新手而言，我已经花了很多时间。
我怎么能解码这样的 URL：
example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0
to this one in python 2.7: example.com?title==правовая+защита
到python 2.7中的这个： example.com?title==правовая+защита
url=urllib.unquote(url.encode("utf8"))is returning something very ugly.
url=urllib.unquote(url.encode("utf8"))正在返回非常丑陋的东西。
Still no solution, any help is appreciated.
仍然没有解决方案，任何帮助表示赞赏。
采纳答案by Martijn Pieters
The data is UTF-8 encoded bytes escaped with URL quoting, so you want to decode, with urllib.parse.unquote(), which handles decoding from percent-encoded data to UTF-8 bytes and then to text, transparently:
数据是使用 URL 引用转义的 UTF-8 编码字节，因此您要解码, with urllib.parse.unquote()，它可以透明地处理从百分比编码数据到 UTF-8 字节然后到文本的解码：
from urllib.parse import unquote
url = unquote(url)
Demo:
演示：
>>> from urllib.parse import unquote
>>> url = 'example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0'
>>> unquote(url)
'example.com?title=правовая+защита'
The Python 2 equivalent is urllib.unquote(), but this returns a bytestring, so you'd have to decode manually:
Python 2 的等价物是urllib.unquote()，但这会返回一个字节串，因此您必须手动解码：
from urllib import unquote
url = unquote(url).decode('utf8')
回答by pavan
If you are using Python 3, you can use urllib.parse
如果您使用的是 Python 3，则可以使用 urllib.parse
url = """example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0"""
import urllib.parse
urllib.parse.unquote(url)
gives:
给出：
'example.com?title=правовая+защита'
