C语言 gcc 错误：声明说明符中有两个或多个数据类型
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gcc error: two or more data types in declaration specifiers
提问by argos.void
gcc says me:
gcc 说我：
cc -O3 -Wall -pedantic -g -c init.c
init.c:6:1: error: two or more data types in declaration specifiers
init.c: In function 'objinit':
init.c:24:1: warning: control reaches end of non-void function
make: *** [init.o] Error 1
the code is:
代码是：
#include "beings.h"
#include "defs.h"
#include "funcs.h"
#include "obj.h"
void objinit(int type, struct object* lstrct){
switch(type){
case WALL:
lstrct->image = WALL_IMG;
lstrct->walk = false;
lstrct->price = 0;
break;
case WAND:
lstrct->image = WAND_IMG;
lstrct->walk = true;
lstrct->price = 70;
break;
case BOOK:
lstrct->image = BOOK_IMG;
lstrct->walk = true;
lstrct->price = 110;
break;
}
}
i know, things like WALL_IMG is on a .h separated file, but whats wrong with my code?
我知道，像 WALL_IMG 这样的东西在一个 .h 分隔的文件中，但是我的代码有什么问题吗？
回答by James McNellis
My psychic debugging powers tell me that it is likely you have a struct definition in obj.hthat is not terminated with a semicolon.
我的通灵调试能力告诉我，您可能有一个结构体定义，obj.h其中没有以分号结尾。
Incorrect:
不正确：
struct object { /* etc. */ }
Correct:
正确的：
struct object { /* etc. */ };
Why do I think this? The errors say:
为什么我会这样想？错误说：
init.c:6:1: error: two or more data types in declaration specifiers
init.c: In function 'objinit':
init.c:24:1: warning: control reaches end of non-void function
The warning says the compiler thinks your function has a non-void return type, yet your function is clearly declared with a voidreturn type. The error says that the compiler thinks your function is declared with multiple types. The most likely explanation is that there is a struct definition in obj.hthat is unterminated.
警告说编译器认为您的函数具有非 void 返回类型，但您的函数明确声明为具有void返回类型。该错误表示编译器认为您的函数是用多种类型声明的。最可能的解释是其中有一个obj.h未终止的结构体定义。
