C语言 如何将整数放入数字数组
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How to put an integer to an array of digits
提问by Destructor
I want to put a number like 123456 in to a array of digits. Could you please give me a hint to the process? Can i define an array with unknown number of elements?
我想将 123456 之类的数字放入数字数组中。你能给我一个过程的提示吗？我可以定义一个元素数量未知的数组吗？
回答by Umang Mehta
First calculate no of digits
首先计算位数
int count = 0;
int n = number;
while (n != 0)
{
n /= 10;
cout++;
}
Now intialize the array and assign the size:
现在初始化数组并分配大小：
if(count!=0){
int numberArray[count];
count = 0;
n = number;
while (n != 0){
numberArray[count] = n % 10;
n /= 10;
count++;
}
}
回答by jxh
If you don't mind using charas the array element type, you can use snprintf():
如果您不介意char用作数组元素类型，则可以使用snprintf()：
char digits[32];
snprintf(digits, sizeof(digits), "%d", number);
Each digit will be represented as the character values '0'though '9'. To get the integer value, subtract the character value by '0'.
'0'尽管每个数字都将表示为字符值'9'。要获得整数值，请将字符值减去'0'。
int digit_value = digits[x] - '0';
回答by Nanhe Kumar
int x[6];
int n=123456;
int i=0;
while(n>0){
x[i]=n%10;
n=n/10;
i++;
}
回答by P0W
"Can i define an array with unknown number of elements ?"
“我可以定义一个元素数量未知的数组吗？”
If the number is too large you can input it as string and then accordingly extract digits from it
如果数字太大，您可以将其输入为字符串，然后相应地从中提取数字
Something like following :
类似于以下内容：
char buf[128];
int *array;
//fscanf(stdin,"%s",buf);
array = malloc(strlen(buf) * sizeof(int)); //Allocate Memory
int i=0;
do{
array[i] = buf[i]-'0'; //get the number from ASCII subtract 48
}while(buf[++i]); // Loop till last but one
回答by Manoj Pandey
Here are teh steps. First, get the size needed to store all the digits in the number -- do a malloc of an array. Next, take the mod of the number and then divide the number by 10. Keep doing this till you exhaust all digits in the number.
这是步骤。首先，获取存储数字中所有数字所需的大小——对数组进行 malloc。接下来，取数字的模数，然后将数字除以 10。继续这样做，直到用完数字中的所有数字。
