C++ 如何让迭代器到达向量的特定位置
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how to get iterator to a particular position of a vector
提问by A. K.
Suppose i have a
假设我有一个
std::vector<int> v
//and ...
for(int i =0;i<100;++i)
v.push_back(i);
now i want an iterator to, let's say 10th element of the vector.
现在我想要一个迭代器，让我们说向量的第 10 个元素。
without doing the following approach
不做以下方法
std::vector<int>::iterator vi;
vi = v.begin();
for(int i = 0;i<10;i++)
++vi;
as this will spoil the advantage of having random access iterator for a vector.
因为这会破坏向量的随机访问迭代器的优势。
回答by Cory Nelson
This will work with any random-access iterator, such as one from vectoror deque:
这将适用于任何随机访问迭代器，例如 fromvector或deque：
std::vector<int>::iterator iter = v.begin() + 10;
If you want a solution that will work for any type of iterator, use next:
如果您想要一个适用于任何类型迭代器的解决方案，请使用next：
std::vector<int>::iterator iter = std::next(v.begin(), 10);
Or if you're not on a C++11 implementation, advance:
或者，如果您不使用 C++11 实现，则advance：
std::vector<int>::iterator iter = v.begin();
std::advance(iter, 10);
回答by pyroscope
Just add 10 to the iterator. They are intended to "feel" like pointers.
只需将 10 添加到迭代器。它们旨在“感觉”像指针。
