java 如何与字符串部分匹配？
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How to partial match with a string?
提问by Crazymango
How can I type partial letters of a word to find this word?
如何输入一个单词的部分字母来找到这个单词？
For example: I have a string array
例如：我有一个字符串数组
String[] s = {"Cartoon", "Cheese", "Truck", "Pizza"};
if I input partial letters, such as "ca","Che" or "piz"
如果我输入部分字母，例如“ca”、“Che”或“piz”
then I can find the whole words for the list.
然后我可以找到列表的整个单词。
Thanks
谢谢
回答by Danyal Sandeelo
stringValue.contains("string that you wanna search");
.containswill do the job, iterate over the loop and keep adding the words in ArrayList<String>for the matched ones.
.contains将完成这项工作，遍历循环并继续ArrayList<String>为匹配的单词添加单词。
This could be a good readon string in java.
这可以很好地阅读java 中的字符串。
.containsis like '%word%'in mysql. There are other functions like .startsWithand .endsWithin java. You may use whatever suits the best.
.contains就像'%word%'在mysql中一样。在java中还有其他功能，如.startsWith和.endsWith。您可以使用最适合的方式。
回答by Imaginary Pumpkin
Try using String#startsWith
List<String> list = new ArrayList<>();
list.add("Apples");
list.add("Apples1214");
list.add("NotApples");
list.stream().map(String::toLowerCase)
.filter(x->x.startsWith("app"))
.forEach(System.out::println);
If you just want the Stringto be contained, then use String#contains
如果您只想String包含 ，则使用String#contains
回答by Rudy B
Assuming you meant
假设你的意思是
String[] s = {"Cartoon", "Cheese", "Truck", "Pizza"};
The easiest option would be to iterate through your string array and do a .contains on each individual String.
最简单的选择是遍历您的字符串数组并对每个单独的字符串执行 .contains 。
for(int i = 0; i < s.length; i++){
if(s[i].contains("car")){
//do something like add to another list.
}
}
This ofcourse does not take caps into concideration. But this can easily be circumvented with .toLowerCare or .toUpperCase.
这当然不考虑上限。但这可以通过 .toLowerCare 或 .toUpperCase 轻松规避。
回答by Abhishek
Try This Logic For Basic
试试这个基本的逻辑
Scanner sc=new Scanner(System.in);
String[] s = {"Cartoon", "Cheese", "Truck", "Pizza",""};
System.out.println("Enter Characters");
String matchCharStr = sc.next();
for (int i = 0; i < s.length; i++) {
if (s[i].toLowerCase().contains(matchCharStr.toLowerCase())) {
System.out.println(s[i]);
}
}
回答by barbakini
First cast all your strings upper or lower case and then use startsWith () method.
首先将所有字符串转换为大写或小写，然后使用 startsWith() 方法。
回答by patrick-hainge
You could use something like
你可以使用类似的东西
String userInput = (new Scanner(System.in)).next();
for (String string : s) {
if (string.toLowerCase().contains(userInput.toLowerCase()) return string;
}
Note that this is only going to return the first string in your list that contains whatever the user gave you so it's fairly imprecise.
请注意，这只会返回列表中包含用户提供给您的任何内容的第一个字符串，因此它相当不精确。
