从文本文件中提取一列 - Python
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Extract a column from text file - Python
提问by hjames
I'm a beginner py.
我是初学者py。
I need to extract the contents of column 12 from a huge flat text file every time a certain word is found within the text file (similar to awk '{print $12}'in Bash) in a Python script.
每次awk '{print $12}'在 Python 脚本的文本文件（类似于Bash）中找到某个单词时，我都需要从巨大的纯文本文件中提取第 12 列的内容。
So far I have (example, not real code):
到目前为止，我有（例如，不是真正的代码）：
word = a_word
for a_word in data:
column12 = data.split()
print(column12[11])
I assumed that I should start counting from 0 as opposed to 1, though I very well may be incorrect.
我认为我应该从 0 而不是 1 开始计数，尽管我很可能是不正确的。
Also, is a forloop correct for this type of code?
另外，for对于这种类型的代码，循环是否正确？
Thanks!
谢谢！
采纳答案by Martijn Pieters
Loop over the open file object:
循环打开文件对象：
with open('somefile') as infile:
for line in infile:
print(line.split()[11])
So, yes, use a forloop and use 0-based indexing.
所以，是的，使用for循环并使用基于 0 的索引。
回答by Madison May
If the columns are text files with delimiter (i.e. space or comma) separated values, you might want to look into python's csv module: http://docs.python.org/2/library/csv.html
如果列是带有分隔符（即空格或逗号）分隔值的文本文件，您可能需要查看 python 的 csv 模块：http: //docs.python.org/2/library/csv.html
