Python 来自 txt 文件程序的字数统计
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Word count from a txt file program
提问by user3068762
I am counting word of a txt file with the following code:
我正在使用以下代码计算 txt 文件的字数：
#!/usr/bin/python
file=open("D:\zzzz\names2.txt","r+")
wordcount={}
for word in file.read().split():
if word not in wordcount:
wordcount[word] = 1
else:
wordcount[word] += 1
print (word,wordcount)
file.close();
this is giving me the output like this:
这给了我这样的输出：
>>>
goat {'goat': 2, 'cow': 1, 'Dog': 1, 'lion': 1, 'snake': 1, 'horse': 1, '???': 1, 'tiger': 1, 'cat': 2, 'dog': 1}
but I want the output in the following manner:
但我希望以下列方式输出：
word wordcount
goat 2
cow 1
dog 1.....
Also I am getting an extra symbol in the output (???). How can I remove this?
此外，我在输出 ( ???) 中得到了一个额外的符号。我怎样才能删除它？
回答by Tim Pietzcker
The funny symbols you're encountering are a UTF-8 BOM (Byte Order Mark). To get rid of them, open the file using the correct encoding (I'm assuming you're on Python 3):
您遇到的有趣符号是 UTF-8 BOM (Byte Order Mark)。要摆脱它们，请使用正确的编码打开文件（我假设您使用的是 Python 3）：
file = open(r"D:\zzzz\names2.txt", "r", encoding="utf-8-sig")
Furthermore, for counting, you can use collections.Counter:
此外，对于计数，您可以使用collections.Counter：
from collections import Counter
wordcount = Counter(file.read().split())
Displaying them is easy as well:
显示它们也很容易：
>>> for item in wordcount.items(): print("{}\t{}".format(*item))
...
snake 1
lion 2
goat 2
horse 3
回答by duck
import sys
file=open(sys.argv[1],"r+")
wordcount={}
for word in file.read().split():
if word not in wordcount:
wordcount[word] = 1
else:
wordcount[word] += 1
for key in wordcount.keys():
print ("%s %s " %(key , wordcount[key]))
file.close();
回答by bistaumanga
#!/usr/bin/python
file=open("D:\zzzz\names2.txt","r+")
wordcount={}
for word in file.read().split():
if word not in wordcount:
wordcount[word] = 1
else:
wordcount[word] += 1
for k,v in wordcount.items():
print k, v
回答by Wesam Na
If you are using graphLab, you can use this function. It is really powerfull
如果您使用的是 graphLab，则可以使用此功能。真的很强大
products['word_count'] = graphlab.text_analytics.count_words(your_text)
回答by Fuji Komalan
FILE_NAME = 'file.txt'
wordCounter = {}
with open(FILE_NAME,'r') as fh:
for line in fh:
# Replacing punctuation characters. Making the string to lower.
# The split will spit the line into a list.
word_list = line.replace(',','').replace('\'','').replace('.','').lower().split()
for word in word_list:
# Adding the word into the wordCounter dictionary.
if word not in wordCounter:
wordCounter[word] = 1
else:
# if the word is already in the dictionary update its count.
wordCounter[word] = wordCounter[word] + 1
print('{:15}{:3}'.format('Word','Count'))
print('-' * 18)
# printing the words and its occurrence.
for (word,occurance) in wordCounter.items():
print('{:15}{:3}'.format(word,occurance))
Word Count
------------------
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examples 2
used 2
development 2
modified 2
open-source 2
回答by Sivaji
#!/usr/bin/python
file=open("D:\zzzz\names2.txt","r+")
wordcount={}
for word in file.read().split():
if word not in wordcount:
wordcount[word] = 1
else:
wordcount[word] += 1
for k,v in wordcount.items():
print k,v
file.close();
回答by Sanj
you can do this:
你可以这样做：
file= open(r'D:\zzzz\names2.txt')
file_split=set(file.read().split())
print(len(file_split))
