php 日期时间加 1 天
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DateTime add 1 day
提问by CreamYGEEK
My Form has 2 fields - Time_from and Time_to
我的表单有 2 个字段 - Time_from 和 Time_to
Now i need to add an entry in my database for each day (If theres is a difference between those days) ex. Time_from = 2013-08-26 08:00:00 and Time_to = 2013-08-28 16:00:00 So in my database i should get 3 entries
现在我需要每天在我的数据库中添加一个条目（如果这些天之间存在差异）例如。Time_from = 2013-08-26 08:00:00 和 Time_to = 2013-08-28 16:00:00 所以在我的数据库中我应该得到 3 个条目
Time_from = 2013-08-26 08:00:00 and Time_to = 2013-08-26 16:00:00
Time_from = 2013-08-27 08:00:00 and Time_to = 2013-08-27 16:00:00
Time_from = 2013-08-28 08:00:00 and Time_to = 2013-08-28 16:00:00
So for that purpose i have made a method, where i first find the difference between those 2 dates and then i'm using a for loop that will run as many days in difference those 2 dates have, and at the end im just adding 1 day.
所以为了这个目的，我做了一个方法，我首先找到这两个日期之间的差异，然后我使用一个 for 循环，该循环将运行这两个日期的差异天数，最后我只添加 1日。
public function createOffer($offer)
{
$time_from = new DateTime($offer->time_from);
$time_to = new DateTime($offer->time_to);
$interval = $time_from->diff($time_to);
for ($counter = 0; $counter <= $interval->d; $counter++) {
$offer->time_from = $time_from->format('Y-m-d H:i:s');
$offer_time_to = new DateTime($time_from->format('Y-m-d'));
$offer_time_to->setTime($time_to->format('H'), $time_to->format('i')
, $time_to->format('s'));
$offer->time_to = $offer_time_to->format('Y-m-d H:i:s');
if ($offer->validate()) {
$offer->save();
}
date_modify($time_from, '+1 day');
}
}
For some reason, the code doesn't work.
出于某种原因，代码不起作用。
When i remove the date_modify field only the first day will be saved in my database (Guess the for loop is only running once then)
当我删除 date_modify 字段时，只有第一天会保存在我的数据库中（猜猜 for 循环只运行一次）
But with the date_modify in my code, only the last day is saved in the database.
但是在我的代码中使用 date_modify 时，只有最后一天保存在数据库中。
回答by liyakat
you can use Add function of Datatime object
您可以使用 Datatime 对象的 Add 函数
here i am giving you one example to add one 1 in your post date like
在这里，我给你一个例子，在你的发布日期中添加一个 1，比如
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P1D'));
echo $date->format('Y-m-d') . "\n";
?>
OUTPUT
输出
2000-01-02
Hope it will sure help you to solve your issue.
希望它一定能帮助您解决您的问题。
回答by Marcio Mazzucato
$date = new DateTime('2017-01-17');
$date->modify('+1 day');
echo $date->format('Y-m-d'); // 2017-01-18
You can do it too:
你也可以这样做：
$dateTo = new \DateTime('1980-12-07 +1 day');
echo $dateTo->format('Y-m-d'); // 1980-12-08
