typescript 使用类型安全定义打字稿泛型
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/17655607/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-10-21 02:50:19 来源:igfitidea点击:
Defining typescript generics with type safety
提问by Tim
Can you define generics with safe types, as you can with c#?
你能用安全类型定义泛型吗,就像用 c# 一样?
E.g.
例如
public bool Foo<T>() where T : struct { /* */ }
Typescript now has generics, but can I perform a similar action?
Typescript 现在有泛型,但我可以执行类似的操作吗?
Thanks.
谢谢。
回答by Tim
Ok it seems you can do this:
好吧,看来你可以这样做:
Foo<T extends IBar>() { /* */ }
And that seems to make all calls require the T to implement IBar
.
这似乎使所有调用都需要 T 来实现IBar
。