BASH 与 sed 的回声
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BASH echo with sed
提问by merlin.metso
I have:
我有：
Location.txt (content)
Location.txt（内容）
some_line1
some_line2
some_line3
region.txt (content)
region.txt（内容）
region1
region2
region3
uri.txt (content)
uri.txt（内容）
/some_text/some_text1/***/
/some_text/***/some_text2/
/***/some_text/some_text3/
I need to create files
我需要创建文件
region1
region2
region3
and each of them have to fill with the following (name of the region instead of stars)
并且他们每个人都必须填写以下内容（地区名称而不是星星）
Example of file region1
文件 region1 示例
/some_text/some_text1/region1/
some_line1
some_line2
some_line3
/some_text/region1/some_text2
some_line1
some_line2
some_line3
/region1/some_text/some_text3
some_line1
some_line2
some_line3
Example of file region2 (name of the region instead of stars)
文件 region2 示例（区域名称而不是星星）
/some_text/some_text1/region2/
some_line1
some_line2
some_line3
/some_text/region2/some_text2
some_line1
some_line2
some_line3
/region2/some_text/some_text3
some_line1
some_line2
some_line3
Now I have
我现在有
#!/bin/bash
while read region
do
while read uri
do
echo $uri >> "/home/user/regions/$region"
done < uri.txt
done < region.txt
This script creates files with names of lines from region.txtand fill it with lines from uri.txt.
此脚本使用 from 的行名称创建文件，region.txt并使用 from的行填充它uri.txt。
But I have to make a lot of files. Each file should be filled with many locations but one line in each location should be changed to line from uri.txt.
但是我必须制作很多文件。每个文件应填充多个位置，但每个位置中的一行应更改为 line from uri.txt。
Looks like I have to use
看起来我必须使用
cat $file|sed 's/^was/now/'
but I dont know how to use it.
但我不知道如何使用它。
Any help please.
请任何帮助。
采纳答案by csikos.balint
If I understand correctly your problem than 3 nested for cycle can do the job.
如果我正确理解您的问题，那么 3 个嵌套 for 循环就可以完成这项工作。
for reg in $(cat region.txt )
do
echo -n > $reg.txt
for uri in $(cat uri.txt )
do
echo "$uri" | sed -e "s/\*\*\*/$reg/g" | tee -a $reg.txt
for loc in $(cat Location.txt )
do
echo $loc | tee -a $reg.txt
done
done
done
Result:
结果：
$ cat region1.txt
/some_text/some_text1/region1/
some_line1
some_line2
some_line3
/some_text/region1/some_text2/
some_line1
some_line2
some_line3
/region1/some_text/some_text3/
some_line1
some_line2
some_line3
I hope this will help!
我希望这个能帮上忙！
回答by glenn Hymanman
I would use awk for this:
我会为此使用 awk：
awk -v loc="$(< Location.txt)" '
NR==FNR {region[]=1;next}
{for (reg in region) {
sub(/\*\*\*/, reg)
f = reg ".txt"
print > f
print loc > f
}}
' region.txt uri.txt
回答by gniourf_gniourf
@user2874004: your script, a little better written:
@user2874004：你的脚本，写得更好一点：
#!/bin/bash
mkdir -p configs # make directory for configs if it doesnt exist
while IFS= read -r reg # read next line from reg.txt
do
while IFS= read -r uri # read next line from uri.txt
do
echo " ${uri//\*\*\*/$reg} {" # make changes
while IFS= read -r loc # read next line from location.txt
do
echo " $loc" # fill in the location
done < location.txt
done < uri.txt > "./config/$reg.txt"
done < region.txt
(I have no idea what it does, though :)).
（虽然我不知道它是做什么的:)）。
回答by merlin.metso
Finaly I used the following, and it works.
最后我使用了以下内容，它有效。
#!/bin/bash
mkdir -p configs # make directory for configs if it doesnt exist
while read reg # read next line from reg.txt
do
if [ -f ./configs/$reg.txt ]; then # if file allready exist then
rm ./configs/$reg.txt # delete it
fi
while read uri # read next line from uri.txt
do
echo " $uri {" | sed -e "s/\*\*\*/$reg/g" >> ./configs/$reg$ # make changes
while read loc # read next line from location.txt
do
echo " $loc" >> ./configs/$reg.txt # fill in the location
done < location.txt
done < uri.txt
done < region.txt
Thank you all for your help.
谢谢大家的帮助。
