Java 如何拆分文件路径以获取文件名？

How to split a file path to get the file name?

提问by Antonio Mailtraq

I have this string in my Android Application:

我的 Android 应用程序中有这个字符串：

/storage/emulated/0/temp.jpg

I need manipulate the string and to split the string for this output:

我需要操作字符串并为此输出拆分字符串：

temp.jpg

I need always take the last element of the string.

我需要总是取字符串的最后一个元素。

How to this output in java?

如何在java中输出？

I would greatly appreciate any help you can give me in working this problem.

我将不胜感激您在解决此问题时能给我的任何帮助。

采纳答案by Stefan Beike

one another possibility:

另一种可能性：

String lStr = "/storage/emulated/0/temp.jpg";
lStr = lStr.substring(lStr.lastIndexOf("/"));
System.out.println(lStr);

回答by arlistan

You can do it with string split: How to split a string in Java

您可以使用字符串拆分来实现：如何在 Java 中拆分字符串

String string = "/storage/emulated/0/temp.jpg";
String[] parts = string.split("/");
String file= parts[parts.length-1]; 

回答by brso05

String string = "/storage/emulated/0/temp.jpg";
String[] splitString = null;
splitString = string.split("/");
splitString[splitString.length - 1];//this is where your string will be

Try using the String function split. It splits the string by your input and returns an array of strings. Just access the last element of the array in your case.

尝试使用 String 函数 split。它根据您的输入拆分字符串并返回一个字符串数组。在您的情况下，只需访问数组的最后一个元素。

回答by Duncan Jones

This is not a string splitting exercise

这不是字符串拆分练习

If you need to get a file namefrom a file path, use the Fileclass:

如果您需要从文件路径中获取文件名，请使用该类：File

File f = new File("/storage/emulated/0/temp.jpg");
System.out.println(f.getName());

Output:

输出：

temp.jpg

回答by Jatin

Try this:

尝试这个：

String path= "/storage/emulated/0/temp.jpg";
String[] parts = path.split("/");
String filename;
if(parts.length>0)
    filename= parts[parts.length-1];