C语言 在 C 中打印 "（双引号）
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/25411644/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Printing " (double quote) in C
提问by Koushik Sarkar
I am writing a C code which reads from a file and generates an intermediate .cfile.
To do so I use fprintf()to print into that intermediate file.
我正在编写一个 C 代码，它从一个文件中读取并生成一个中间.c文件。为此，我使用fprintf()打印到该中间文件中。
How can I print "?
如何打印"？
回答by Vlad from Moscow
You can use escape symbol \"For example
您可以使用转义符号\"例如
puts( "\"This is a sentence in quotes\"" );
or
或者
printf( "Here is a quote %c", '\"' );
or
或者
printf( "Here is a quote %c", '"' );
回答by Keith Thompson
If you just want to print a single "character:
如果您只想打印单个"字符：
putchar('"');
The "doesn't have to be escaped in a character constant, since character constants are delimited by ', not ". (You can still escape it if you like: '\"'.)
在"不具有字符常量转义，因为字符常量被分隔'，没有"。（如果你愿意，你仍然可以逃避它：'\"'。）
If it's part of some larger chunk of output in a string literal, you need to escape it so it's not treated as the closing "of the literal:
如果它是字符串文字中较大输出块的一部分，则需要对其进行转义，以免将其视为"文字的结束：
puts("These are \"quotation marks\"\n");
or
或者
printf("%s\n", "These are \"quotation marks\"");
