java Java中Iterator的c#等价物是什么
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what is the c# equivalent of Iterator in Java
提问by peter.murray.rust
I am manually converting Java to C# and have the following code:
我手动将 Java 转换为 C# 并具有以下代码：
for (Iterator<SGroup> theSGroupIterator = SGroup.getSGroupIterator();
theSGroupIterator.hasNext();)
{
SGroup nextSGroup = theSGroupIterator.next();
}
Is there an equivalent of Iterator<T>in C# or is there a better C# idiom?
是否有Iterator<T>C# 中的等价物，或者是否有更好的 C# 习惯用法？
回答by Lee
The direct equivalent in C# would be IEnumerator<T>and the code would look something like this:
C# 中的直接等价物是IEnumerator<T>，代码看起来像这样：
SGroup nextSGroup;
using(IEnumerator<SGroup> enumerator = SGroup.GetSGroupEnumerator())
{
while(enumerator.MoveNext())
{
nextSGroup = enumerator.Current;
}
}
However the idiomatic way would be:
然而，惯用的方式是：
foreach(SGroup group in SGroup.GetSGroupIterator())
{
...
}
and have GetSGroupIteratorreturn an IEnumerable<T>(and probably rename it to GetSGroups()or similar).
并GetSGroupIterator返回一个IEnumerable<T>（并且可能将其重命名为GetSGroups()或类似）。
回答by casperOne
In .NET in general, you are going to use the IEnumerable<T>interface. This will return an IEnumerator<T>which you can call the MoveNext method and Current property on to iterate through the sequence.
通常在 .NET 中，您将使用该IEnumerable<T>接口。这将返回一个IEnumerator<T>，您可以调用 MoveNext 方法和 Current 属性来遍历序列。
In C#, the foreach keyword does all of this for you. Examples of how to use foreach can be found here:
在 C# 中，foreach 关键字会为您完成所有这些工作。可以在此处找到如何使用 foreach 的示例：
http://msdn.microsoft.com/en-us/library/ttw7t8t6(VS.80).aspx
http://msdn.microsoft.com/en-us/library/ttw7t8t6(VS.80).aspx
回答by Andrew Keith
Yes, in C#, its called an Enumerator.
是的，在 C# 中，它被称为Enumerator。
回答by Marek
Even though this is supported by C# via IEnumerator/IEnumerable, there is a better idiom: foreach
尽管 C# 通过 IEnumerator/IEnumerable 支持这一点，但还有一个更好的习惯用法：foreach
foreach (SGroup nextSGroup in items)
{
//...
}
for details, see MSDN: http://msdn.microsoft.com/en-us/library/aa664754(VS.71).aspx
有关详细信息，请参阅 MSDN：http: //msdn.microsoft.com/en-us/library/aa664754(VS.71).aspx
