ASP.NET/JavaScript - 为什么“返回假”不阻止回发？
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ASP.NET/JavaScript - Why Isn't "Return False" Not Preventing Postback?
提问by RPM1984
I feel like i've done this scenario plenty of times, and it usually works, so im obviously missing something.
我觉得我已经做了很多次这种情况，而且它通常有效，所以我显然错过了一些东西。
Here's my server-side ASP.NET Button:
这是我的服务器端 ASP.NET 按钮：
<asp:Button ID="btnFoo" runat="server" Text="Foo" CssClass="button foo" OnClientClick="foo_Click();" />
Which get's rendered on the client as:
哪个 get 在客户端呈现为：
<input type="submit" name="reallylongclientid" value="Foo" onclick="foo_Click();WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(reallylongclientidandpostbackoptions, false, false))" id="reallylongclientid" class="button foo">
No surprises there.
那里没有惊喜。
Here's the surprise, in my JavaScript function:
这是我的 JavaScript 函数中的惊喜：
function foo_Click() {
return false;
}
Okay so there's more to it than that, but i cut it down to prove a point.
好吧，除此之外还有更多内容，但我将其删减以证明一点。
When i click the button, it calls the client-side function, and returns false.
当我单击按钮时，它调用客户端函数，并返回 false。
But it still posts back to the server, why?
但它仍然回发到服务器，为什么？
I basically want to do this on the click of the button:
我基本上想通过点击按钮来做到这一点：
- Do client-side validation.
- If validation passes, post back
- If not, show some error messages on the form.
- 进行客户端验证。
- 如果验证通过，回发
- 如果没有，请在表单上显示一些错误消息。
Of course, i could change this to an client-side button (input type="button") and manuallykick off the postback when i want, but i shouldn't need to do that. Or should i?
当然，我可以将其更改为客户端按钮（输入类型 =“按钮”）并在需要时手动启动回发，但我不需要这样做。还是我应该？
回答by Pranay Rana
write returnstatement so when you click on button it return falsewhich not allow to submit form
编写return声明，以便当您单击return false不允许提交表单的 按钮时
<asp:Button ID="btnFoo" runat="server" Text="Foo" CssClass="button foo"
OnClientClick="return foo_Click();" />
