javascript 带有自定义获取 URL 的 Backbone.js

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时间:2020-10-27 11:42:18  来源:igfitidea点击:

Backbone.js with a custom fetch URL

javascriptbackbone.js

提问by Keith Hymanson

I am trying to set up a variant fetch method on my backbone model that will fetch the current model for a given user. This is available from the API on /api/mealplans/owner/{username}/current.

我正在尝试在我的主干模型上设置一个变体获取方法,该方法将为给定用户获取当前模型。这可以从 上的 API 获得/api/mealplans/owner/{username}/current

I have written the following model. I commented out the URL Root, as the prototype fetch call was simply using the urlRootand I wanted to see if that was overriding the url parameter I passed in portions somehow.

我编写了以下模型。我注释掉了 URL Root,因为原型 fetch 调用只是使用urlRoot,我想看看它是否覆盖了我以某种方式传入的 url 参数。

var mealPlan = Backbone.Model.extend({
  name: 'Meal Plan',
  //urlRoot: '/api/mealplans',
  defaults: {},
  fetchCurrent: function (username, attributes, options) {
    attributes = attributes || {};
    options = options || {};
    if (options.url === undefined) {
      options.url = "/api/mealplans/owner/" + username + "/current";
    }
    return Backbone.Model.prototype.fetch.call(this, attributes, options);
  },
  validate: function (attributes) {
    // To be done
    return null;
  }
});

I've seen this done, in some variations in other places, such as at backbone.js use different urls for model save and fetch- In that case the code is slightly different (I started with that and broke it down to make it easier for me to read.)

我已经看到这样做了,在其他地方的一些变化中,例如在backbone.js 使用不同的 url 进行模型保存和获取- 在这种情况下,代码略有不同(我从它开始并将其分解以使其更容易供我阅读。)

The options object has the url parameter in it fine when I pass it to fetch, but then it seems to ignore it!

当我将它传递给 fetch 时,options 对象中的 url 参数很好,但它似乎忽略了它!

回答by Keith Hymanson

I was assuming the same parameters to fetch as to save - This is not the case.

我假设要获取的参数与要保存的参数相同 - 情况并非如此。

The method signature for fetch ONLY takes 'options' and not 'attributes', hence the url parameter wasn't found.

fetch 的方法签名仅采用“选项”而不是“属性”,因此未找到 url 参数。

The model code should look a bit more like this..

模型代码应该看起来更像这样..

   var mealPlan = Ministry.Model.extend({

        name: 'Meal Plan',
        urlRoot: '/api/mealplans',

        defaults: {
        },

        fetchCurrent: function (username, options) {
            options = options || {};
            if (options.url === undefined) {
                options.url = this.urlRoot + "/owner/" + username + "/current";
            }

            return Backbone.Model.prototype.fetch.call(this, options);
        },

        validate: function (attributes) {
            // To be done
            return null;
        }
    });

回答by Nadir

I think it is better to override url() method, like below:

我认为最好覆盖 url() 方法,如下所示:

 var mealPlan = Ministry.Model.extend({

    name: 'Meal Plan',
    urlRoot: '/api/mealplans',

    //--> this gets called each time fetch() builds its url
    url: function () { 
        //call the parent url()
        var url=Backbone.Model.prototype.url.call(this);
        //here you can transform the url the way you need
        url += "?code=xxxx";
        return url;
    }
 ...

besides, in your example above I think there is a mistake and you should replace fetchCurrentby fetch

除此之外,在你上面的例子我认为这是一个错误,你应该更换fetchCurrent通过