Python 如何检查特定整数是否在列表中
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How to check if a specific integer is in a list
提问by FigNeutron
I want to know how to make an if statement that executes a clause if a certain integer is in a list.
我想知道如果某个整数在列表中，如何制作一个执行子句的 if 语句。
All the other answers I've seen ask for a specific condition like prime numbers, duplicates, etc. and I could not glean the solution to my problem from the others.
我见过的所有其他答案都要求特定条件，如素数、重复数等，但我无法从其他人那里收集到我的问题的解决方案。
采纳答案by That1Guy
You could simply use the inkeyword. Like this :
您可以简单地使用in关键字。像这样 ：
if number_you_are_looking_for in list:
# your code here
For instance :
例如 ：
myList = [1,2,3,4,5]
if 3 in myList:
print("3 is present")
回答by That1Guy
Are you looking for this?:
你在找这个吗？：
if n in my_list:
---do something---
Where nis the number you're checking. For example:
n你查的号码在哪里。例如：
my_list = [1,2,3,4,5,6,7,8,9,0]
if 1 in my_list:
print 'True'
回答by Justin MacCreery
I think the above answers are wrong because of this situation:
由于这种情况，我认为上述答案是错误的：
my_list = [22166, 234, 12316]
if 16 in my_list:
print( 'Test 1 True' )
else:
print( 'Test 1 False' )
my_list = [22166]
if 16 in my_list:
print( 'Test 2 True' )
else:
print( 'Test 2 False' )
Would produce: Test 1 False Test 2 True
会产生： 测试 1 假 测试 2 真
A better way:
更好的方法：
if ininstance(my_list, list) and 16 in my_list:
print( 'Test 3 True' )
elif not ininstance(my_list, list) and 16 == my_list:
print( 'Test 3 True' )
else:
print( 'Test 3 False' )
