bash 在现有子目录中递归创建目录树
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Recursively create directory tree within existing subdirectories
提问by ap123
I have a working directory with a large number of subfolders (i.e 1190A, 1993A etc).
我有一个包含大量子文件夹（即 1190A、1993A 等）的工作目录。
'/working/1190A'
'/working/1993A'
I would like to recursively create a certain directory tree within each subfolder. For example:
我想在每个子文件夹中递归地创建一个特定的目录树。例如：
'/working/1190A/analysis/1'
'/working/1993A/analysis/1'
etc
Thanks.
谢谢。
回答by fedorqui 'SO stop harming'
To force the system create a directory tree without having to create each level of it, add -pto the mkdircommand.
要强制系统创建目录树而不必创建它的每个级别，请添加-p到mkdir命令中。
Hence, this could work:
因此，这可以工作：
for dir in list_of_folders
do
mkdir -p $dir/your/directory/tree
[ $? ] && echo "error on $dir" # if the dir could not be created, print error (thanks @hetepeperfan - see comments)
done
Note that the list_of_folderscan be given like /working/1190A /working/1993A, but also generated with a findcommand. This is just a first version you'd better adapt to your specific requirements.
请注意，list_of_folders可以像 一样给出/working/1190A /working/1993A，但也可以用find命令生成。这只是您最好适应您的特定要求的第一个版本。
回答by Rohan
This is one liner as
这是一个班轮
cd /working
find . -maxdepth 1 -type d -exec mkdir -p '{}'/analysis/1 \;
回答by vpram86
yourDirList=/working/*
for f in $yourDirList
do
if [ -d $f ]
mkdir -p $f/analysis/1
fi
done
