从 C++ 程序在 Linux 中运行另一个程序
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Run Another Program in Linux from a C++ Program
提问by Vincent Russo
Okay so my question is this. Say I have a simple C++ code:
好的，所以我的问题是这个。假设我有一个简单的 C++ 代码：
#include <iostream>
using namespace std;
int main(){
cout << "Hello World" << endl;
return 0;
}
Now say I have this program that I would like to run in my program, call it prog. Running this in the terminal could be done by:
现在说我有一个我想在我的程序中运行的程序，称之为 prog。在终端中运行它可以通过以下方式完成：
./prog
Is there a way to just do this from my simple C++ program? For instance
有没有办法从我的简单 C++ 程序中做到这一点？例如
#include <iostream>
using namespace std;
int main(){
./prog ??
cout << "Hello World" << endl;
return 0;
}
Any feedback would be very much obliged.
非常感谢任何反馈。
采纳答案by J. C. Salomon
回答by elimirks
You could us the system command:
您可以使用系统命令：
system("./prog");
回答by gmoney
You could use a system call like this: http://www.cplusplus.com/reference/clibrary/cstdlib/system/
您可以使用这样的系统调用：http: //www.cplusplus.com/reference/clibrary/cstdlib/system/
Careful if you use user input as a parameter, its a good way to have some unintended consequences. Scrub everything!
如果您使用用户输入作为参数，请小心，这是产生一些意外后果的好方法。擦洗一切！
Generally, system calls can be construed as bad form.
通常，系统调用可以被解释为错误的形式。
回答by xda1001
You can also use popen
您也可以使用 popen
#include <stdio.h>
int main(void)
{
FILE *handle = popen("./prog", "r");
if (handle == NULL) {
return 1;
}
char buf[64];
size_t readn;
while ((readn = fread(buf, 1, sizeof(buf), handle)) > 0) {
fwrite(buf, 1, readn, stdout);
}
pclose(handle);
return 0;
}
