获取Android App的Linux UID
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Obtain the Linux UID of an Android App
提问by Erez A. Korn
I would like to be able to get the Linux UID (user ID) of an installed Android application.
我希望能够获取已安装的 Android 应用程序的 Linux UID（用户 ID）。
Excerpt from Security and Permissions: "At install time, Android gives each package a distinct Linux user ID. The identity remains constant for the duration of the package's life on that device."
摘自安全和权限：“在安装时，Android 为每个包提供了一个不同的 Linux 用户 ID。该身份在包在该设备上的生命周期内保持不变。”
Is there a way to retrieve this UID?
有没有办法检索这个UID？
采纳答案by CommonsWare
Use PackageManagerand getApplicationInfo().
使用PackageManager和getApplicationInfo()。
回答by pavan
- The ?
packages.xmlfile present in/data/system - The
packages.listfile present in/data/system
- 这 ？
packages.xml文件存在于/data/system - 该
packages.list文件存在于/data/system
Contain the list of applications installed and their corresponding UID's.
包含已安装的应用程序列表及其相应的 UID。
回答by Joe Bowbeer
adb shell dumpsys package com.example.myapp | grep userId=
adb shell dumpsys package com.example.myapp | grep userId=
回答by Ege Kuzubasioglu
PackageManager packageManager = getPackageManager();
try {
applicationId = String.valueOf(packageManager.getApplicationInfo("com.example.app", PackageManager.GET_META_DATA));
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
回答by Matt Ke
As CommonsWare already wrote, you can use PackageManagerto get the UID.
正如CommonsWare 已经写的那样，您可以使用它PackageManager来获取UID。
Here's an example:
下面是一个例子：
int uid;
try {
ApplicationInfo info = context.getPackageManager().getApplicationInfo(
context.getPackageName(), 0);
uid = info.uid;
} catch (PackageManager.NameNotFoundException e) {
uid = -1;
}
Log.i(LOG_TAG, "UID = " + uid);
回答by lyind
Use android.os.Process.myUid()to get the calling apps UID directly.
用于android.os.Process.myUid()直接获取调用应用程序 UID。
Using the PackageManager is not necessary to find the own UID.
不需要使用 PackageManager 来查找自己的 UID。
