如何在文本文件中搜索单词并用 Python 打印部分行？
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How to search for word in text file and print part of line with Python?
提问by hjames
I'm writing a Python script. I need to search a text file for a word and then print part of that line. My problem is that the word will not be an exact match in the text file.
我正在编写一个 Python 脚本。我需要在文本文件中搜索一个单词，然后打印该行的一部分。我的问题是这个词在文本文件中不会完全匹配。
For example, in the below text file example, I'm searching for the word "color=".
例如，在下面的文本文件示例中，我正在搜索单词"color=".
Text File ex:
文本文件例如：
ip=10.1.1.1 color=red house=big
ip=10.1.1.2 color=green house=small
ip=10.1.1.3 animal = dog house=beach
ip=10.1.1.4 color=yellow house=motorhome
If it finds it, it should print to a new text file "color=color", not the whole line.
如果找到它，它应该打印到一个新的文本文件"color=color"，而不是整行。
Result Text File ex:
结果文本文件例如：
color=red
color=green
color=yellow
My code:
我的代码：
for line_1 in open(file_1):
with open(line_1+'.txt', 'a') as my_file:
for line_2 in open(file_2):
line_2_split = line_2.split(' ')
if "word" in line_2:
if "word 2" in line_2:
for part in line_2:
line_part = line_2.split(): #AttributeError: 'list' object has no attribute 'split'
if "color=" in line_part():
print(line_part)
I believe I need to use regular expressions or something like line.find("color="), but I'm not sure what or how.
我相信我需要使用正则表达式或类似的东西line.find("color=")，但我不确定是什么或如何。
Question: How do I search a text file for a word (not an exact match) and the print only a specific part of each line?
问题：如何在文本文件中搜索一个词（不是完全匹配）并只打印每行的特定部分？
采纳答案by Brionius
Here's one way - split each line by spaces, then search each part for "color=":
这是一种方法 - 用空格分割每一行，然后在每个部分中搜索“color=”：
with open("textfile.txt") as openfile:
for line in openfile:
for part in line.split():
if "color=" in part:
print part
回答by kirbyfan64sos
Well, it may not be much, but you could always use regex:
好吧，它可能不多，但你总是可以使用正则表达式：
m = re.search(r'(color\=.+?(?= )|color\=.+?$)', line)
if m:
text = m.group() # Matched text here
