如果在 Java 中的字符串中有多个空格，如何将它们压缩为单词之间的单个空格？
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If you have multiple spaces inside a string in Java, how do you condense them into a single space between words?
提问by Bruce Philby
If a string has multiple spaces between words:
如果字符串在单词之间有多个空格：
The cat sat on the mat.
How do you make it a single space?
你如何使它成为一个单一的空间？
The cat sat on the mat.
I tried this but it didn't work:
我试过这个，但没有用：
myText = myText.trim().replace(" ", " ");
回答by Lukas Eder
With a regular expression:
使用正则表达式：
myText.trim().replaceAll("\s+", " ");
This reads: "trim text and then replace all occurrences of one or more than one whitespace character (including tabs, line breaks, etc) by one single whitespace"
内容如下：“修剪文本，然后用一个空格替换所有出现的一个或多个空格字符（包括制表符、换行符等）”
See also java.util.regex.Pattern for more details on Java regular expressions:
有关 Java 正则表达式的更多详细信息，另请参见 java.util.regex.Pattern：
http://download.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html
http://download.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html
回答by Yuriy
All you need:
一切你需要的：
myText.replaceAll("\s++", " ");
Accordigng to specs of replaceAllmethod of class String: http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String)
replaceAll根据类的方法规范String：http: //docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String )
and specs of Patternclass in java(try to ctrl-F for "whitespace", and "++" ):
http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html
和PatternJava 类的规范（尝试按 ctrl-F 表示“空白”和“++”）：http:
//docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern。 html
In my opinion it's much better to open those pages and take a look by yourself, then just to copy snippet.
在我看来，最好打开这些页面并自己查看，然后复制代码段。
