错误：使用“{...}”初始化聚合对象 - C++
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error: initialization with "{...}" expected for aggregate object - c++
提问by pistal
struct test
{
unsigned int test1;
unsigned char test2[4096];
unsigned int test3;
} foo
struct foobar
{
unsigned char data[4096];
}
if i want to access the struct, i say foo.test1, foo.test2[4096], etc.. however, when I wish to return the data present in foo.test2 in the following manner
如果我想访问结构，我会说 foo.test1、foo.test2[4096] 等等。但是，当我希望以下列方式返回 foo.test2 中存在的数据时
pac.datafoo = foo.test2[4096];
unsigned char data[4096] = pac.datafoo;
this is the error I get:
这是我得到的错误：
error: initialization with "{...}" expected for aggregate object
what is the mistake i'm doing?
我在做什么错误？
回答by Charlie
You need to learn the array initialization method. It's NOT simply assigned as the single variable.
你需要学习数组初始化方法。它不是简单地分配为单个变量。
Some examples:
一些例子：
int arrayone[3] = {0}; // assign all items with 0
int arraytwo[3] = {1, 2, 3 }; // assign each item with 1, 2 and 3
int arraythree[3]; // assign arraythree with arraytwo
for (int i = 0; i < 3; ++i) {
arraythree[i] = arraytwo[i];
}
回答by Steve
add ";" at the end of the struct.
添加 ”;” 在结构的末尾。
struct test
{
unsigned int test1;
unsigned char test2[4096];
unsigned int test3;
} foo ;
struct foobar
{
unsigned char data[4096];
} ;
回答by SChalice
unsigned char * data;
data = pac.datafoo;
