如何将用户输入读入 Bash 中的变量？
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How to read user input into a variable in Bash?
提问by Geofferey
I'm trying to create a script that simplifies the process of creating a new user on an iOS device. Here are the steps broken down.
我正在尝试创建一个脚本，以简化在 iOS 设备上创建新用户的过程。以下是分解的步骤。
# fullname="USER INPUT"
# user="USER INPUT"
# group=$user
# uid=1000
# gid=1000
# home=/var/$user
# echo "$group:*:$gid:$user" >> /private/etc/group
# echo "$user::$uid:$gid::0:0:$fullname:$home:/bin/sh" >> /private/etc/master.passwd
# passwd $user
# mkdir $home
# chown $user:$group $home
As you can see some fields require input. How can I request input for a variable in script?
如您所见，某些字段需要输入。如何在脚本中请求输入变量？
回答by konsolebox
Use read -p:
使用read -p：
# fullname="USER INPUT"
read -p "Enter fullname: " fullname
# user="USER INPUT"
read -p "Enter user: " user
If you like to confirm:
如果您想确认：
read -p "Continue? (Y/N): " confirm && [[ $confirm == [yY] || $confirm == [yY][eE][sS] ]] || exit 1
You should also quote your variables to prevent pathname expansion and word splitting with spaces:
您还应该引用您的变量以防止路径名扩展和用空格进行分词：
# passwd "$user"
# mkdir "$home"
# chown "$user:$group" "$home"
回答by jjulien
Yep, you'll want to do something like this:
是的，你会想要做这样的事情：
echo -n "Enter Fullname: "
read fullname
Another option would be to have them supply this information on the command line. Getopts is your best bet there.
另一种选择是让他们在命令行上提供此信息。Getopts 是您最好的选择。
Using getopts in bash shell script to get long and short command line options
回答by Aleks-Daniel Jakimenko-A.
回答by Nishant Ingle
Try this
尝试这个
#/bin/bash
read -p "Enter a word: " word
echo "You entered $word"
