bash 脚本在目录中创建多个目录
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bash script create multiple directories within directories
提问by ibash
I want to create a directory structure like this in nix:
我想在 nix 中创建这样的目录结构：
mkdir -p 1,2,3,4,5,6,7,8,9and within each of these folders I want folders 1,2,3,4,5,6,7,8,9
mkdir -p 1,2,3,4,5,6,7,8,9在这些文件夹中的每一个中，我想要文件夹 1,2,3,4,5,6,7,8,9
I have started to write a simple loop like this (all the way up to folder 2) but this seems inefficient.
我已经开始写一个像这样的简单循环（一直到文件夹 2），但这似乎效率低下。
#!/usr/bin/env bash
for i in 1 2 4 5 6 7 8 9; do mkdir -p 1/{1,2,3,4,5,6,7,8,9} $i, mkdir -p 2/{1,2,3,4,5,6,7,8,9} ; done
Is there a better way of doing it?
有更好的方法吗？
回答by Micha? Kosmulski
This should help (requires bash):
这应该会有所帮助（需要 bash）：
mkdir -p {1,2,3,4,5,6,7,8,9}/{1,2,3,4,5,6,7,8,9}
Some newer versions of bash also allow this:
一些较新版本的 bash 也允许这样做：
mkdir -p {1..9}/{1..9}
回答by David Kennedy
Sounds simple enough unless I've misunderstood:
除非我误解，否则听起来很简单：
#!/bin/sh
for i in `seq 1 9`; do
for j in `seq 1 9`; do
mkdir -p $i/$j
done
done
回答by Debaditya
Perl Solution.
Perl 解决方案。
for($counter = 1; $counter <= 9; $counter++)
{
`mkdir -p $counter/{1..9}`; //Executing Unix Command
}
