bash unix set 命令集——“$@”“$i”的意思
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unix set command set -- “$@” "$i" meaning
提问by Teddy
I am confused for the one line bash script
我对一行 bash 脚本感到困惑
for i in "$@"
do
set -- "$@" "$i" // what does it mean?
done
I can understand $@ is all the variables which passing in, and i is every element which in $@, However, I can't figure what does
我可以理解 $@ 是传入的所有变量，而 i 是 $@ 中的每个元素，但是，我不知道是什么
set -- "$@" "$i"
means.
方法。
Thanks.
谢谢。
回答by chepner
It's appending the value of $ionto the end of the positional parameters. Not sure whyone would want to do it, but it's basically a verbose way of doubling the parameters. It has the same affect as
它将 的值附加$i到位置参数的末尾。不知道为什么要这样做，但它基本上是一种将参数加倍的冗长方式。它具有相同的影响
$ set -- a b c
$ echo "$@"
a b c
$ set -- "$@" "$@"
echo "$@"
a b c a b c
