php 带有 file_get_contents 的 HTTP 请求，获取响应代码
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HTTP requests with file_get_contents, getting the response code
提问by georg
I'm trying to use file_get_contentstogether with stream_context_createto make POST requests. My code so far:
我正在尝试file_get_contents与 with 一起使用stream_context_create来发出 POST 请求。到目前为止我的代码：
$options = array('http' => array(
'method' => 'POST',
'content' => $data,
'header' =>
"Content-Type: text/plain\r\n" .
"Content-Length: " . strlen($data) . "\r\n"
));
$context = stream_context_create($options);
$response = file_get_contents($url, false, $context);
It works fine, however, when an HTTP error occurs, it spits out a warning:
它工作正常，但是，当发生 HTTP 错误时，它会发出警告：
file_get_contents(...): failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request
and returns false. Is there a way to:
并返回假。有没有办法：
- suppress a warning (I'm planning to throw my own exception in case of failure)
- obtain the error information (at least, the response code) from the stream
- 抑制警告（我打算在失败的情况下抛出我自己的异常）
- 从流中获取错误信息（至少是响应码）
回答by Alles
http://php.net/manual/en/reserved.variables.httpresponseheader.php
http://php.net/manual/en/reserved.variables.httpresponseheader.php
file_get_contents("http://example.com", false, stream_context_create(['http' => ['ignore_errors' => true]]));
var_dump($http_response_header);
回答by mindplay.dk
None of the answers (including the one accepted by OP) actually satisfy the two requirements:
没有一个答案（包括 OP 接受的答案）实际上满足两个要求：
- suppress a warning (I'm planning to throw my own exception in case of failure)
- obtain the error information (at least, the response code) from the stream
- 抑制警告（我打算在失败的情况下抛出我自己的异常）
- 从流中获取错误信息（至少是响应码）
Here's my take:
这是我的看法：
function fetch(string $method, string $url, string $body, array $headers = []) {
$context = stream_context_create([
"http" => [
// http://docs.php.net/manual/en/context.http.php
"method" => $method,
"header" => implode("\r\n", $headers),
"content" => $body,
"ignore_errors" => true,
],
]);
$response = file_get_contents($url, false, $context);
/**
* @var array $http_response_header materializes out of thin air
*/
$status_line = $http_response_header[0];
preg_match('{HTTP\/\S*\s(\d{3})}', $status_line, $match);
$status = $match[1];
if ($status !== "200") {
throw new RuntimeException("unexpected response status: {$status_line}\n" . $response);
}
return $response;
}
This will throw for a non-200response, but you can easily work from there, e.g. add a simple Responseclass and return new Response((int) $status, $response);if that fits your use-case better.
这将引发无200响应，但您可以轻松地从那里开始工作，例如添加一个简单的Response类，return new Response((int) $status, $response);如果它更适合您的用例。
For example, to do a JSON POSTto an API endpoint:
例如，要POST对 API 端点执行 JSON ：
$response = fetch(
"POST",
"http://example.com/",
json_encode([
"foo" => "bar",
]),
[
"Content-Type: application/json",
"X-API-Key: 123456789",
]
);
Note the use of "ignore_errors" => truein the httpcontext map - this will prevent the function from throwing errors for non-2xx status codes.
请注意"ignore_errors" => true在http上下文映射中的使用- 这将防止函数为非 2xx 状态代码抛出错误。
This is most likely the "right" amount of error-suppression for most use-cases - I do not recommend using the @error-suppression operator, as this will also suppress errors like simply passing the wrong arguments, which could inadvertently hide a bug in calling code.
对于大多数用例，这很可能是“正确”的错误抑制量 - 我不建议使用@错误抑制运算符，因为这也会抑制错误，例如简单地传递错误的参数，这可能会无意中隐藏错误调用代码。
回答by hamboy75
Adding few more lines to the accepted response to get the http code
在接受的响应中添加更多行以获取 http 代码
function getHttpCode($http_response_header)
{
if(is_array($http_response_header))
{
$parts=explode(' ',$http_response_header[0]);
if(count($parts)>1) //HTTP/1.0 <code> <text>
return intval($parts[1]); //Get code
}
return 0;
}
@file_get_contents("http://example.com");
$code=getHttpCode($http_response_header);
to hide the error output both comments are ok, ignore_errors = true or @ (I prefer @)
隐藏错误输出两个注释都可以，ignore_errors = true 或@（我更喜欢@）
回答by Besen
@file_get_contentsand ignore_errors = trueare not the same:
the first doesn't return anything;
the second suppresses error messages, but returns server response (e.g. 400 Bad request).
@file_get_contents并且ignore_errors = true不一样：第一个不返回任何内容；第二个抑制错误消息，但返回服务器响应（例如 400 Bad request）。
I use a function like this:
我使用这样的函数：
$result = file_get_contents(
$url_of_API,
false,
stream_context_create([
'http' => [
'content' => json_encode(['value1' => $value1, 'value2' => $value2]),
'header' => 'Authorization: Basic XXXXXXXXXXXXXXX',
'ignore_errors' => 1,
'method' => 'POST',
'timeout' => 10
]
])
);
return json_decode($result)->status;
It returns 200 (Ok) or 400 (Bad request).
它返回 200（好的）或 400（错误的请求）。
It works perfectly and it's easier than cURL.
它工作得很好，而且比 cURL 更容易。
回答by Kaarel
I go to this page with kind of a different issue, so posting my answer. My problem was that I was just trying to suppress the warning notification and display a customized warning message for the user, so this simple and obvious fix helped me:
我带着一个不同的问题去这个页面，所以发布我的答案。我的问题是我只是想抑制警告通知并为用户显示自定义警告消息，所以这个简单而明显的修复帮助了我：
// Suppress the warning messages
error_reporting(0);
$contents = file_get_contents($url);
if ($contents === false) {
print 'My warning message';
}
And if needed, turn back error reporting after that:
如果需要，在此之后返回错误报告：
// Enable warning messages again
error_reporting(-1);
