Java/ 从 long 到 SimpleDateFormat 再到时间戳
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Java/ From long to SimpleDateFormat and to Timestamp
提问by Adam Sh
I wrote a function that got a Timestamp (year, month, day, hour, min and sec) as a parameter.
我写了一个函数，它以时间戳（年、月、日、小时、分钟和秒）作为参数。
I just now find that instead of getting a Timestamp type, I got a long type - after the next stpes:
我刚刚发现不是得到 Timestamp 类型，而是得到了 long 类型 - 在下一个 stpes 之后：
The constructor is:
构造函数是：
protected SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
and then:
接着：
long qu = dateFormat.parse("24.12.2011 18:54:23").getTime();
I try to find how to convert the qu, back to SimpleDateFormat and then to Timestamp, or directly: from long to Timestamp (But where long was created after these two steps).
我试图找到如何将 qu，转换回 SimpleDateFormat 然后转换为 Timestamp，或直接：从 long 转换为 Timestamp (But where long was created after these two steps)。
eariler, I ask how to convert long to Timestamp.The answer was given is correct, but Im afraid that this is not the case when I convert it from SimpleDateFormat to long (the function doesn't work after the change).
早些时候，我问如何将 long 转换为 Timestamp。给出的答案是正确的，但是当我将其从 SimpleDateFormat 转换为 long 时，恐怕情况并非如此（该函数在更改后不起作用）。
Thanks.
谢谢。
回答by GriffeyDog
This works for me:
这对我有用：
public class Test {
public static void main(String... args) {
SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
try {
long qu = dateFormat.parse("24/12/2011 18:54:23").getTime();
Timestamp ts = new Timestamp(qu);
System.out.println(ts);
} catch (ParseException e) {
e.printStackTrace();
}
}
}
Outputs: 2011-12-24 18:54:23.0
输出：2011-12-24 18:54:23.0
