python 2.7中的超级
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/38072278/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
super in python 2.7
提问by ikel
I'm trying to understand how to use superin python
我试图了解如何super在 python 中使用
class people:
name = ''
age = 0
__weight = 0
def __init__(self,n,a,w):
self.name = n
self.age = a
self.__weight = w
def speak(self):
print("%s is speaking: I am %d years old" %(self.name,self.age))
class student(people):
grade = ''
def __init__(self,n,a,w,g):
#people.__init__(self,n,a,w)
super(student,self).__init__(self,n,a,w)
self.grade = g
def speak(self):
print("%s is speaking: I am %d years old,and I am in grade %d"%(self.name,self.age,self.grade))
s = student('ken',20,60,3)
s.speak()
The above code gets following error:
上面的代码得到以下错误：
---------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-147-9da355910141> in <module>()
10
11
---> 12 s = student('ken',20,60,3)
13 s.speak()
<ipython-input-147-9da355910141> in __init__(self, n, a, w, g)
3 def __init__(self,n,a,w,g):
4 #people.__init__(self,n,a,w)
----> 5 super(student).__init__(self,n,a,w)
6 self.grade = g
7
TypeError: must be type, not classobj
I'm confused about why I cannot use super(student,self).__init__(self,n,a,w)in this case, and why I have to use people.__init__(self,n,a,w)
我很困惑为什么我不能super(student,self).__init__(self,n,a,w)在这种情况下使用，为什么我必须使用people.__init__(self,n,a,w)
Any help?
有什么帮助吗？
回答by Simon Callan
Your base class peopleshould be derived from the objectclass, to make it a new-style class, which will allow super()to work.
你的基类people应该从object类派生出来，使其成为一个新式类，这将允许super()工作。
You should then use superas:
然后你应该使用super：
super(student, self).__init__(n,a,w)
Old-style classes behave quite differently, and I don't understand them
旧式类的行为完全不同，我不理解它们
