php 解析错误：语法错误，意外的“$query”（T_VARIABLE）
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Parse error: syntax error, unexpected '$query' (T_VARIABLE)
提问by BenniMcBeno
Evening all,
晚上大家，
I am having an issue with this script and i'm hoping one of you fine programmers could let me know where the error is.
我遇到了这个脚本的问题，我希望你们中的一位优秀的程序员可以让我知道错误在哪里。
<?php
mysql_connect("127.0.0.1", "root", "") or die (mysql_error());
echo "Connected to MYSQL ";
mysql_select_db("tutorial") or die (mysql_error());
echo "Connected to Data Base"
$query = "SELECT * FROM forr1";
$result = mysql_query ($query) or die (mysql_error());
while ($row = mysql_fetch_array($result)) {
echo $row['input1'];
?>
The Output
输出
Parse error: syntax error, unexpected '$query' (T_VARIABLE) in C:\Program Files (x86)\EasyPHP-12.1\www\Output.php on line 7
I must be missing something significant because no matter how i try and rework it i get the same error.
我一定遗漏了一些重要的东西，因为无论我如何尝试和返工，我都会遇到同样的错误。
Thanks for your time
谢谢你的时间
Ben
本
回答by Grant Thomas
Missing semi-colon on the line prior:
前一行缺少分号：
echo "Connected to Data Base"
Terminate the statement:
终止声明：
echo "Connected to Data Base";
