Java 如何将以下 JSON 字符串转换为 POJO

How to convert the following JSON String to POJO

提问by Arsen Davtyan

I want to convert the following JSONstring to a Javaobject:

我想将以下JSON字符串转换为Java对象：

{
  "user": {
    "0": {
      "firstName": "Monica",
      "lastName": "Belluci"
    },
    "1": {
      "firstName": "John",
      "lastName": "Smith"
    },
    "2": {
      "firstName": "Owen",
      "lastName": "Hargreaves"
    }
  }
}

To convert this to Javaobject I've created the following classes:

为了将其转换为Java对象，我创建了以下类：

class User {
    private Map<String, MyObject> user = new HashMap<>();
    //Getter and Setter is here
}

class MyObject {
    private String firstName;
    private String lastName;
    //Getters and Setters are here
}

I'm using Hymansonlibrary to convert JSONto Java. Here is how I'm using the Hymanson for conversion:

我正在使用Hymanson库转换JSON为Java. 这是我如何使用 Hymanson 进行转换：

ObjectMapper mapper = new ObjectMapper();
User user = mapper.readValue(jsonString, User.class);

The problem is that with this conversion above the Mapinside the User object is always empty. What am I doing wrong?

问题是上面的这个转换Map里面的 User 对象总是空的。我究竟做错了什么？

Thanks in advance.

提前致谢。

采纳答案by K. Gol

I think it should work. I've executed this code and it works fine. Here is my example.

我认为它应该工作。我已经执行了这段代码，它工作正常。这是我的例子。

import com.fasterxml.Hymanson.databind.ObjectMapper;
import java.io.IOException;

public class TestHymanson {

public static void main(String[] args) throws IOException {
        ObjectMapper mapper = new ObjectMapper();
        String testJson = "{\n" + "  \"user\": {\n" + "    \"0\": {\n" + "      \"firstName\": \"Monica\",\n" + "      \"lastName\": \"Belluci\"\n" + "    },\n" + "    \"1\": {\n" + "      \"firstName\": \"John\",\n" + "      \"lastName\": \"Smith\"\n" + "    },\n" + "    \"2\": {\n" + "      \"firstName\": \"Owen\",\n" + "      \"lastName\": \"Hargreaves\"\n" + "    }\n" + "  }\n" + "}";
        User readValue = mapper.readValue(testJson, User.class);
        System.out.println("readValue = " + readValue);
    }
}

and the User.class:

和 User.class：

import java.util.HashMap;
import java.util.Map;

class User {
    private Map<String, MyObject> user = new HashMap<String, MyObject>();

    public Map<String, MyObject> getUser() {
        return user;
    }

    public void setUser(Map<String, MyObject> user) {
        this.user = user;
    }

    @Override
    public String toString() {
        return "User{" +
                "user=" + user +
                '}';
    }
}

class MyObject {
    private String firstName;
    private String lastName;

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public String getLastName() {
        return lastName;
    }

    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    @Override
    public String toString() {
        return "MyObject{" +
                "firstName='" + firstName + '\'' +
                ", lastName='" + lastName + '\'' +
                '}';
    }
}

回答by Pratik Mohanrao Gondil

Use can done with the help of gson library.

使用可以在 gson 库的帮助下完成。

import java.io.IOException;
import java.io.InputStreamReader;
import java.io.Reader;
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

public class JsonToJava {

    public static void main(String[] args) throws IOException {
        try(Reader reader = new InputStreamReader(JsonToJava.class.getResourceAsStream("/Server2.json"), "UTF-8")){
            Gson gson = new GsonBuilder().create();
            Person p = gson.fromJson(reader, YourPOJOClass.class);
            System.out.println(p);
        }
    }
}

visit this linkhope this helps :)

访问此链接希望这会有所帮助:)

回答by lahirumw

You can try below code, It works fine..

你可以试试下面的代码，它工作正常..

public class User {

    private Map<String, Map<String, String>> user;

    public Map<String, Map<String, String>> getUser() {
        return user;
    }

    public void setUser(Map<String, Map<String, String>> user) {
        this.user = user;
    }

}


public class JsonCast {

    public static void main(String args[]) {

        String response = "{\"user\" : {\"0\": {\"firstName\": \"Monica\",\"lastName\": \"Belluci\"},\"1\": { \"firstName\": \"John\",\"lastName\": \"Smith\"}}}";

        ObjectMapper mapper = new ObjectMapper();
        try {

            User user = mapper.readValue(response, User.class);

            System.out.println(user.getUser().get("0"));

        } catch (IOException e) {

            e.printStackTrace();
        }
    }

}

回答by she12

I had one additional issue, that i faced when converting JSON to Java POJO: com.fasterxml.Hymanson.databind.JsonMappingException: Can not deserialize instance of class out of START_ARRAY token ...

我在将 JSON 转换为 Java POJO 时遇到了一个额外的问题： com.fasterxml.Hymanson.databind.JsonMappingException: Can not deserialize instance of class out of START_ARRAY token ...

If anyone faces this issue, this is because JSON is expecting an object {}but it sees an array [{}]within the JSON String that is passed in

如果有人遇到这个问题，这是因为 JSON 期望的是 anobject {}但它array [{}]在传入的 JSON 字符串中看到了

ObjectMapper mapper = new ObjectMapper();
User user = mapper.readValue(jsonString, User.class);

To fix

修理

User[] user = mapper.readValue(jsonString, User[].class);

Reference: https://stackoverflow.com/a/33515796/4167786

参考：https: //stackoverflow.com/a/33515796/4167786