Linux 通过命令行恢复停止的进程
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Resume a stopped process through command line
提问by Ajish Alfred
I've executed the following C code in Linux CentOS to create a process.
我已经在 Linux CentOS 中执行了以下 C 代码来创建一个进程。
#include <stdio.h>
#include <unistd.h>
int main ()
{
int i = 0;
while ( 1 )
{
printf ( "\nhello %d\n", i ++ );
sleep ( 2 );
}
}
I've compiled it to hello_count. When I do ./hello_count, The output is like this:
我已将其编译为hello_count. 当我这样做时./hello_count，输出是这样的：
hello 0
hello 1
hello 2
...
till I kill it. I've stopped the execution using the following command
直到我杀了它。我已使用以下命令停止执行
kill -s SIGSTOP 2956
When I do
当我做
ps -e
the process 2956 ./hello_countis still listed.
该过程2956 ./hello_count仍被列出。
Is there any command or any method to resume (not to restart) the process having process id 2956?
是否有任何命令或任何方法可以恢复（而不是重新启动）进程 ID 为 2956 的进程？
Also, when I stop the process, the command line shows:
此外，当我停止进程时，命令行显示：
[1]+ Stopped ./hello_count
What does the [1]+in the above line mean?
什么是[1]+在上面的线是什么意思？
回答by tuxuday
- To continue a stopped process, that is resume use kill -SIGCONT PID
- Regd [1]+ that is bash way of handling jobs. For further information try help jobsfrom bash prompt.
- 要继续停止的进程，即恢复使用kill -SIGCONT PID
- Regd [1]+ 是 bash 处理作业的方式。有关更多信息，请尝试从 bash 提示符尝试帮助作业。
