Java 在函数中将 Scanner 对象作为参数传递的基本语法
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Basic Syntax for passing a Scanner object as a Parameter in a Function
提问by hayonj
Here is what I wrote which is pretty basic :
这是我写的非常基本的内容：
import java.util.Scanner;
public class Projet {
/**
* @param args
* @param Scanner
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("Enter a digit");
Scanner in = new Scanner(System.in);
getChoice(Scanner);
in.close();
}
public static int getChoice(Scanner n){
n = in.nextInt();
return n;
}
}
What seems to be wrong here ? I had it working earlier, I had to pass the Scanner typeand argument nameas a parameter to the function... and simply call that function in the main using Scanner type and argumentas an argument to the function ?
这里似乎有什么问题？我早些时候让它工作了，我必须将Scanner 类型和参数名称作为参数传递给函数......并简单地使用Scanner 类型和参数作为函数的参数在主函数中调用该函数？
-----EDIT-----
- - -编辑 - - -
New Code below for below that will need it :
下面的新代码将需要它：
import java.util.Scanner;
public class Projet {
/**
* @param args
* @param Scanner
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("Enter a digit");
Scanner in = new Scanner(System.in);
System.out.println(getChoice(in));
in.close();
}
public static int getChoice(Scanner in){
return in.nextInt();
}
}
@rgettman Thanks !
@rgettman 谢谢！
采纳答案by rgettman
You need to pass the actual variable name inwhen you call the method, not the class name Scanner.
in调用方法时需要传递实际变量名，而不是类名Scanner。
getChoice(in);
instead of
代替
getChoice(Scanner);
Incidentally, your getChoicemethod won't compile as shown. Just return what the scanner returns, which is an int, as you declared getChoiceto return an int:
顺便说一句，您的getChoice方法不会如图所示编译。只需返回扫描仪返回的内容，即int，正如您声明getChoice要返回的一样int：
public static int getChoice(Scanner n){
return n.nextInt();
}
