Python 在列表中查找最旧/最年轻的日期时间对象
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Find oldest/youngest datetime object in a list
提问by panosl
I've got a list of datetime objects, and I want to find the oldest or youngest one. Some of these dates might be in the future.
我有一个日期时间对象列表,我想找到最老或最年轻的对象。其中一些日期可能在未来。
from datetime import datetime
datetime_list = [
datetime(2009, 10, 12, 10, 10),
datetime(2010, 10, 12, 10, 10),
datetime(2010, 10, 12, 10, 10),
datetime(2011, 10, 12, 10, 10), #future
datetime(2012, 10, 12, 10, 10), #future
]
What's the most optimal way to do so? I was thinking of comparing datetime.now() to each one of those.
这样做的最佳方法是什么?我正在考虑将 datetime.now() 与其中的每一个进行比较。
采纳答案by eumiro
Oldest:
最老的:
oldest = min(datetimes)
Youngest before now:
以前最年轻:
now = datetime.datetime.now(pytz.utc)
youngest = max(dt for dt in datetimes if dt < now)
回答by Gabi Purcaru
Datetimes are comparable; so you can use max(datetimes_list)and min(datetimes_list)
日期时间具有可比性;所以你可以使用max(datetimes_list)和min(datetimes_list)
回答by JoshD
Given a list of dates dates:
给定日期列表dates:
Max date is max(dates)
最大日期是 max(dates)
Min date is min(dates)
最小日期是 min(dates)
回答by jknair
have u tried this :
你有没有试过这个:
>>> from datetime import datetime as DT
>>> l =[]
>>> l.append(DT(1988,12,12))
>>> l.append(DT(1979,12,12))
>>> l.append(DT(1979,12,11))
>>> l.append(DT(2011,12,11))
>>> l.append(DT(2022,12,11))
>>> min(l)
datetime.datetime(1979, 12, 11, 0, 0)
>>> max(l)
datetime.datetime(2022, 12, 11, 0, 0)
回答by Malik A. Rumi
The datetime module has its own versions of min and max as available methods. https://docs.python.org/2/library/datetime.html
datetime 模块有自己的 min 和 max 版本作为可用方法。https://docs.python.org/2/library/datetime.html

