如何使用 JavaScript 仅针对 Internet Explorer 11?

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时间:2020-10-27 08:22:45  来源:igfitidea点击:

How can I target only Internet Explorer 11 with JavaScript?

javascriptinternet-explorerbrowserinternet-explorer-11

提问by dave1010

What's the least error-prone way to target just IE11 with JavaScript?

使用 JavaScript 仅针对 IE11 的最不容易出错的方法是什么?

Note: This should really only be done for analytics or informing the user what browser they're using. For everything else, there's feature detection.

注意:这实际上应该仅用于分析或通知用户他们正在使用的浏览器。对于其他一切,都有特征检测。

回答by Denys Séguret

The User-agent string for IE 11 is currently this one :

IE 11 的用户代理字符串目前是这样的:

Mozilla/5.0 (Windows NT 6.3; Trident/7.0; rv 11.0) like Gecko

Windows 10 example:

Windows 10 示例:

Mozilla/5.0 (Windows NT 10.0; Trident/7.0; rv:11.0) like Gecko

Which means your can simply test, for versions 11.xx,

这意味着您可以简单地测试 11.xx 版本,

var isIE11 = /Trident.*rv[ :]*11\./.test(navigator.userAgent);

As IE10 user agent was

由于IE10 用户代理是

Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.2; Trident/6.0)

it's probably also safe to bet on the fact that now Trident/Xis supposed to be the real versionning.

可以肯定的是,现在Trident/X应该是真正的版本控制。

回答by dave1010

IE11 keeps "Trident" in it's UA string, but drops MSIE. A simple way to detect the browser is IE11 or above (IE12, IE13, etc) is:

IE11 在它的 UA 字符串中保留“Trident”,但丢弃 MSIE。检测浏览器是否为 IE11 或以上(IE12、IE13 等)的简单方法是:

var isAtLeastIE11 = !!(navigator.userAgent.match(/Trident/) && !navigator.userAgent.match(/MSIE/));

If you want justIE11 (and you don't want future versions of IE to match), do this:

如果您想要IE11(并且您不希望 IE 的未来版本匹配),请执行以下操作:

var isIE11 = !!(navigator.userAgent.match(/Trident/) && navigator.userAgent.match(/rv[ :]11/));

回答by Florian Margaine

回答by Fredrik Borggren

I use the following pattern to target all IE browsers. You can short it down if you only need IE 11.

我使用以下模式来定位所有 IE 浏览器。如果您只需要 IE 11,则可以将其缩短。

 /msie|trident|edge/g.test(navigator.userAgent.toLowerCase());

Good luck!

祝你好运!

Fredrik

弗雷德里克

回答by baisakhi chauhan

Here's a script you can use to detect any browser:

这是一个可用于检测任何浏览器的脚本:

<script>

  // Opera
  var isOpera = (!!window.opr && !!opr.addons) || !!window.opera || navigator.userAgent.indexOf(' OPR/') >= 0;

  // Firefox 1.0+
  var isFirefox = typeof InstallTrigger !== 'undefined';

  // Safari 3.0+ "[object HTMLElementConstructor]" 
  var isSafari = /constructor/i.test(window.HTMLElement) || (function (p) { return p.toString() === "[object SafariRemoteNotification]"; })(!window['safari'] || safari.pushNotification);

  // Internet Explorer 6-11
  var isIE = /*@cc_on!@*/false || !!document.documentMode;

  // Edge 20+
  var isEdge = !isIE && !!window.StyleMedia;

  // Chrome 1+
  var isChrome = !!window.chrome && !!window.chrome.webstore;

  // Blink engine detection
  var isBlink = (isChrome || isOpera) && !!window.CSS;

  if (isFirefox==true) {
    alert(isFirefox)
    $('.container-fluid').css({"overflow-y":"auto","height":"150%"});  
  }

</script>

回答by Rohan Kumar

Try this,

试试这个,

navigator.sayswho= (function(){
   var N= navigator.appName, ua= navigator.userAgent, tem;
   var M= ua.match(/(opera|chrome|safari|firefox|msie)\/?\s*(\.?\d+(\.\d+)*)/i);
   if(M && (tem= ua.match(/version\/([\.\d]+)/i))!= null) M[2]= tem[1];
   M= M? [M[1], M[2]]: [N, navigator.appVersion,'-?'];
   return M;
})();

Source from Browser detection in JavaScript?

来自JavaScript 中的浏览器检测?

Updated for IE=11

更新为IE=11

Use this

用这个

var isIE11 = navigator.userAgent.match(/Trident\/7.0; rv 11.0/);

Read this http://msdn.microsoft.com/en-us/library/ie/bg182625%28v=vs.85%29.aspx

阅读此http://msdn.microsoft.com/en-us/library/ie/bg182625%28v=vs.85%29.aspx

回答by Beejor

This will set ieto the version of IE, or 0 if none. It'll work for 1 through 11, but may not detect future versions if Microsoft drops the Trident engine.

这将设置ie为 IE 的版本,如果没有,则设置为 0。它适用于 1 到 11,但如果 Microsoft 放弃 Trident 引擎,则可能无法检测到未来的版本。

var ie = 0;
try { ie = navigator.userAgent.match( /(MSIE |Trident.*rv[ :])([0-9]+)/ )[ 2 ]; }
catch(e){}

You may also be interested in my related, more detailed answer here.

您可能也有兴趣在我相关,更详细的答案在这里