php 如何从命令行执行类中的方法
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How do you execute a method in a class from the command line
提问by dan.codes
Basically I have a PHP class that that I want to test from the commandline and run a certain method. I am sure this is a basic question, but I am missing something from the docs. I know how to run a file, obviously php -fbut not sure how to run that file which is a class and execute a given method
基本上我有一个 PHP 类，我想从命令行测试它并运行某个方法。我确定这是一个基本问题，但我从文档中遗漏了一些东西。我知道如何运行文件，显然php -f但不知道如何运行作为类的文件并执行给定的方法
回答by netcoder
This will work:
这将起作用：
php -r 'include "MyClass.php"; MyClass::foo();'
But I don't see any reasons do to that besides testing though.
但我认为除了测试之外没有任何理由这样做。
回答by J.C. Inacio
I would probably use call_user_func to avoid harcoding class or method names. Input should probably use some kinf of validation, though...
我可能会使用 call_user_func 来避免对类或方法名称进行硬编码。输入可能应该使用某种验证，但......
<?php
class MyClass
{
public function Sum($a, $b)
{
$sum = $a+$b;
echo "Sum($a, $b) = $sum";
}
}
// position [0] is the script's file name
array_shift(&$argv);
$className = array_shift(&$argv);
$funcName = array_shift(&$argv);
echo "Calling '$className::$funcName'...\n";
call_user_func_array(array($className, $funcName), $argv);
?>
Result:
结果：
E:\>php testClass.php MyClass Sum 2 3
Calling 'MyClass::Sum'...
Sum(2, 3) = 5
回答by Sander Marechal
Here's a neater example of Repox's code. This will only run de method when called from the commandline.
这是 Repox 代码的一个更简洁的示例。这只会在从命令行调用时运行 de 方法。
<?php
class MyClass
{
public function hello()
{
return "world";
}
}
// Only run this when executed on the commandline
if (php_sapi_name() == 'cli') {
$obj = new MyClass();
echo $obj->hello();
}
?>
回答by Repox
As Pekka already mentioned, you need to write a script that handles the execution of the specific method and then run it from your commandline.
正如 Pekka 已经提到的，您需要编写一个脚本来处理特定方法的执行，然后从命令行运行它。
test.php:
测试.php：
<?php
class MyClass
{
public function hello()
{
return "world";
}
}
$obj = new MyClass();
echo $obj->hello();
?>
And in your commandline
在你的命令行中
php -f test.php
