objective-c 将字符串转换为 NSDate
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/2311421/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Converting a string to an NSDate
提问by hugo411
How is it possible to convert a string to an NSDateon iOS?
如何将字符串转换为NSDateiOS 上的字符串？
回答by Suresh Thayu
NSString *dateStr = @"20100223";
// Convert string to date object
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyyMMdd"];
NSDate *date = [dateFormat dateFromString:dateStr];
// Convert date object to desired output format
[dateFormat setDateFormat:@"EEEE MMMM d, YYYY"];
dateStr = [dateFormat stringFromDate:date];
[dateFormat release];
Hope this will help you.
希望这会帮助你。
回答by Giao
You'll want to take a look at NSDateFormatter. Determine the format of the date string and then use dateFromString:to convert the string to an NSDate object.
你会想看看NSDateFormatter。确定日期字符串的格式，然后用于dateFromString:将字符串转换为 NSDate 对象。
回答by Niketan Rana
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"dd/MM/YYYY"];
NSDate *date = [dateFormat dateFromString:dateStr];
list = [self getYear:date];
- (NSMutableArray *)getYear:(NSDate*)date
{
NSDateComponents *components = [[NSCalendar currentCalendar] components:NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear fromDate:date];
int year = [components year];
int month = [components month];
int day = [components day];
NSLog(@"%d",year);
NSMutableDictionary *dateDict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:[NSString stringWithFormat:@"%d", day], @"day", [NSString stringWithFormat:@"%d", month], @"month", [NSString stringWithFormat:@"%d", year], @"year", nil];
return dateDict;
}
回答by OhadM
A simple approacheven if you have sqlite DB:
即使您有 sqlite 数据库，一个简单的方法：
// NSTimeInterval is basically typedef of double so you can receive it as double also.
NSTimeInterval *current = [[NSDate date] timeIntervalSince1970];
[DB addToDB:current];
//retrieve the date from DB
NSDate *retrievedDateItem = [[NSDate alloc] initWithTimeIntervalSince1970:[getDBValueAsDouble]]; //convert it from double (NSTimeInterval) to NSDate
// Set the style
[dateFormatter setDateStyle:NSDateFormatterMediumStyle];
[dateFormatter setTimeStyle:NSDateFormatterMediumStyle];
// Converted to string
NSString *convertedDate = [dateFormatter stringFromDate:retrievedDateItem];
The output for this example:
此示例的输出：
Aug 3, 2015, 12:27:50 PM
2015 年 8 月 3 日下午 12:27:50
回答by Raphael Souza
My working version in Swift
我在 Swift 中的工作版本
func dateFor(timeStamp: String) -> NSDate
{
let formater = NSDateFormatter()
formater.dateFormat = "HH:mm:ss:SSS - MMM dd, yyyy"
return formater.dateFromString(timeStamp)!
}
func timeStampFor(date: NSDate) -> String
{
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "HH:mm:ss:SSS - MMM dd, yyyy"
return dateFormatter.stringFromDate(date)
}
回答by Gank
+(NSDate*)str2date:(NSString*)dateStr{
if ([dateStr isKindOfClass:[NSDate class]]) {
return (NSDate*)dateStr;
}
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyy-MM-dd"];
NSDate *date = [dateFormat dateFromString:dateStr];
return date;
}
